Let a, b, c, and d, be positive integer constants with a < b. Without using the arithmetic sum formula, prove that (c(a + b) + 2d) (b – a + 1) > (ci + d) = %3D 2 i=a a-1 (ci + d) = ci - ci + d i=a i=1 i=1 i=a cb(b + 1) c(a– 1)a | + (b – a + 1)d c(b² + b– (a² – a)) 2d(b – a + 1) | 2 2 c(b? +b- a2 + a), 2d(b - a+ 1) + 2 2 c(b2 - a2 +b+ a) , 2d(b – a + 1) + c((b- a)(b + a) + (b + a)) , 2d(b - a + 1) + | 2 + a)(b- a + 1), 2d(b – a + 1) 2 (c(a + b) + 2d)(b – a + 1) 2

Solve. |x-2+6=9 State the two equations that arise after writing the equation in the form |X|= a and removing the absolute value signs. Select the correct choice below. O A. x-2+6=9, x-2+6=-9 OB. x-2=9, x-2=-9 O C. x-2=3, x-2=3 O D. x-2=0, x+2=0 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. The solution(s) is/are (Simplify your answer. Type an integer or a fraction. Use a comma to separate answers as needed.) ○ B. There is no solution.

Can you please show me how to solve this?

A flagpole that is 24 feet tall casts a shadow that is 8 feet long, and man that is 6 feet tall casts a shadow that is x feet long. What is the value of x?   Which of the following equations best models the problem above?