fx = 3 - x**3 - x**5 - 2.7183**-xNR iteration on the addion picture part ı uploaded examplewith a precision of 4digits and the inital guess of 2.0000Please write a Pyhton code for NR iteration solution of the previous function. Implementation of the derivative should be an approximation through limit theorem. Xo = 5.0000f (xo)= 5f'(xo)f (5)= 5f'(5)121.272X1 = X0= 3.400975.8391f (x1)= 3.4009f'(x1)f(3.4009)35.0884X2 = X1= 3.4009= 2.3637f'(3.4009)33.8305f(x2)f'(x2)f(x3)f'(x3)f (2.3637)f'(2.3637)f(1.7841)f'(1.7841)9.7069X3 = X2 -= 2.3637= 2.3637= 1.784116.74681.8859X4 = X3= 1.7841= 1.7841= 1.603810.4596f(x4)f'(x4)f(1.6038)0.1584X5 = X4 –= 1.6038 -= 1.6038= 1.5856f'(1.6038)8.7145f (x5)f'(xs)f(1.5856)f'(1.5856)0.0016X6 = X5= 1.5856 -= 1.5856= 1.58558.5423

Answered: lease write a Pyhton code for NR…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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fx = 3 - x**3 - x**5 - 2.7183**-x

NR iteration on the addion picture part ı uploaded example

with a precision of 4digits and the inital guess of 2.0000

Please write a Pyhton code for NR iteration solution of the previous function. Implementation of the derivative should be an approximation through limit theorem.

Xo = 5.0000
f (xo)
= 5
f'(xo)
f (5)
= 5
f'(5)
121.272
X1 = X0
= 3.4009
75.8391
f (x1)
= 3.4009
f'(x1)
f(3.4009)
35.0884
X2 = X1
= 3.4009
= 2.3637
f'(3.4009)
33.8305
f(x2)
f'(x2)
f(x3)
f'(x3)
f (2.3637)
f'(2.3637)
f(1.7841)
f'(1.7841)
9.7069
X3 = X2 -
= 2.3637
= 2.3637
= 1.7841
16.7468
1.8859
X4 = X3
= 1.7841
= 1.7841
= 1.6038
10.4596
f(x4)
f'(x4)
f(1.6038)
0.1584
X5 = X4 –
= 1.6038 -
= 1.6038
= 1.5856
f'(1.6038)
8.7145
f (x5)
f'(xs)
f(1.5856)
f'(1.5856)
0.0016
X6 = X5
= 1.5856 -
= 1.5856
= 1.5855
8.5423

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