Determine V and I of a short transmission line, if Z is... a) 600+ j2002 and 200 + j300 are in parallel then in series with a 200 resistor b) 200 , 5H and 15µF in parallel 23020°V 60Hz j200 102 I M N V

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter4: Transmission Line Parameters
Section: Chapter Questions
Problem 4.32MCQ
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Basic Electrical Engineering (UPVOTE WILL BE GIVEN. PLEASE WRITE THE COMPLETE SOLUTIONS LEGIBLYNO LONG EXPLANATION NEEDED. ANSWER IN 4 DECIMAL PLACESBOX THE FINAL ANSWERS.

Determine V and I of a short transmission line, if Z is...
a) 600+ j200 and 200 + j300 are in parallel then in series with a
200 Q resistor
b) 200 Q2, 5H and 15µF in parallel
20°V
23020°V
60Hz
j20Ω
102 I
M
N
V
Transcribed Image Text:Determine V and I of a short transmission line, if Z is... a) 600+ j200 and 200 + j300 are in parallel then in series with a 200 Q resistor b) 200 Q2, 5H and 15µF in parallel 20°V 23020°V 60Hz j20Ω 102 I M N V
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2. Determine V and I of a short transmission line, if Z is... V=IR
a) 500+j300
b) 1000 and 10μF in parallel,
V=12
E-
230Z0°V
60Hz
a) I = = =
I=
j10Ω
4Ω
W
Z V
500
+j300
23020
Z¯¯ (4+;10)+(506+)300)
I = 0.3311 - 10.2036 A
1 = 0.3887 / -31.5948 A
V= IZ
V = (2.3311-j0.2036) (500+1300)
|V= 226.63-j247 V
100=
Zeq=
2015- (100 + - 035 2032
-j243.
3.2582
10 мF
217 (6=) (10x106)
Xc= 265.2582
*с= -јXc
Zea = 87.5563-j33.00Br Xc= -j265.2582
Zeq= 93.5715 <20.65652
Z₁ = (4 + jlo) + (87.5563-j 33.008)
2₂=91.5563-j23.008
23020
E
Z
911.5533-j23.008
V=226.6435 <0.6244 v I=2.3629 + 50.59384
2 TT fC
v=1 Zeq
V = (2.3629+,0598) (87,55638
V=226.487-j26.0037 v
V=227.97482-6.5496 V
Transcribed Image Text:2. Determine V and I of a short transmission line, if Z is... V=IR a) 500+j300 b) 1000 and 10μF in parallel, V=12 E- 230Z0°V 60Hz a) I = = = I= j10Ω 4Ω W Z V 500 +j300 23020 Z¯¯ (4+;10)+(506+)300) I = 0.3311 - 10.2036 A 1 = 0.3887 / -31.5948 A V= IZ V = (2.3311-j0.2036) (500+1300) |V= 226.63-j247 V 100= Zeq= 2015- (100 + - 035 2032 -j243. 3.2582 10 мF 217 (6=) (10x106) Xc= 265.2582 *с= -јXc Zea = 87.5563-j33.00Br Xc= -j265.2582 Zeq= 93.5715 <20.65652 Z₁ = (4 + jlo) + (87.5563-j 33.008) 2₂=91.5563-j23.008 23020 E Z 911.5533-j23.008 V=226.6435 <0.6244 v I=2.3629 + 50.59384 2 TT fC v=1 Zeq V = (2.3629+,0598) (87,55638 V=226.487-j26.0037 v V=227.97482-6.5496 V
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