Law School Admissions Test (LSAT) scores are approximately normally distributed with a mean of 150 and standard deviation of 10. The typical law student at Yale has an LSAT score of 170. If we randomly pick a LSAT taker, what is the probability they score higher than the typical law student at Yale? A. 0.023 В. О.159 С. 0.841 D 0 977

Lecture(10.1): The mean of the population is 50. The standard deviation is 10. (a) What is the probablity that a randomly  selected person from a population has a mean score between 50 and 75 ? (b) if a person Z score is 1.38. what is his raw score? (c) if a person has raw score of -.91. What is his raw score?.

Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the probability of a bone density test score greater than -1.89. G -1.89 1.89 1.89 -1.89 -1.89 Click to select your answer(s). MUItimeaia LIprary ITest 2 Review Quiz [Chapters 5&6] Optional but encour...

The song-length of tunes in the Big Hair playlist of a Statistics professor's mp3-player varies from song to song. This variation can be modeled by the Normal distribution, with a mean song-length of u = 4.3 minutes and a standard deviation of o 0.65 minutes. Note that a song that has a length of 4.5 minutes is a song that lasts for 4 minutes and 30 seconds. = While listening to a song, the professor decides to shuffle the playlist, which means the mp3-player is to randomly pick a song within this particular playlist, and play this next. If using/working with z-values, use three decimals. (a) What is the probability that the next song to be played is between 3.6 and 4.6 minutes long? Answer to four decimals. (b) What proportion of all the songs in this playlist are longer than 5 minutes? Use four decimals in your answer. (c) 10% of all the songs in this playlist are at most how long, in minutes? Enter your answer to two decimals, and keep your answer consistent with how the song length…

ANOVA was used to test the outcomes of three drug treatments. Each drug was given to 20 individuals. The MSE for this analysis was 16. What is the standard deviation for all 60 individuals sampled for this study? А. 16 В. 48 С. 6.928 D. 4

Safari File Edit View History Bookmarks Window Help Wed 10:51 A myopenmath.com Netflix MyOpenMath b My Questions | bartleby You are conducting a study to see if the probability of catching the flu this year is significantly less than 0.16. Your sample data produce the test statistic z = - 3.214. Find the p-value accurate to 4 decimal places. Submit Question

A particular fruit's weights are normally distributed, with a mean of 539 grams and a standard deviation of 13 grams.If you pick 15 fruit at random, what is the probability that their mean weight will be between 549 grams and 550 grams

The amount of time spent by customers in a store follows a normal distribution with a mean of 30 minutes and a standard deviation of 5 minutes. What is the probability that a randomly selected customer spends between 25 and 35 minutes in the store? The IQ scores of a population follow a normal distribution with a mean of 100 and a standard deviation of 15. What percentage of the population has an IQ score between 85 and 115?

A particular fruit's weights are normally distributed, with a mean of 483 grams and a standard deviation of 23 grams.If you pick 17 fruits at random, then 16% of the time, their mean weight will be greater than how many grams

bout 4% of the population has a particular genetic mutation. 300 people are randomly selected.Find the standard deviation for the number of people with the genetic mutation in such groups of 300. (Remember that standard deviation should be rounded to one more decimal place than the raw data, in this case 1 decimal place is necessary.)