Lauryl alcohol (C12H26O) is obtained from coconut oil and is used to make detergents. A solution of 5.00 g of lauryl alcohol in 0.100 kg of benzene (C6H6) freezes at 4.1°C. What is the approximate molar mass of lauryl alcohol if the freezing point of lauryl alcohol is 5.5°C and its Kf=5.12°C/m?

The vapor pressure of water is 23.76 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in water is glucose.Calculate the vapor pressure of the solution at 25 °C when 6.800 grams of glucose, C6H12O6 (180.2 g/mol), are dissolved in 267.7 grams of water.water = H2O = 18.02 g/mol.VP(solution) =         mm Hg

4. A 6.06-gram sample of a compound is dissolved in 250. grams of benzene. The freezing point of this solution is 1.02°C below that of pure benzene. What is the molar mass of this compound? (Note: Kę for benzene = 5.12°C/m.)

The normal freezing point of a certain liquid X is 0.60°C, but when 0.14 kg of barium hydroxide (BaOH2) are dissolved in 900.g of X the solution freezes at −1.6°C instead. Use this information to calculate the molal freezing point depression constant Kf of X. Round your answer to 2 significant digits.

When 224. mg of a certain molecular compound X are dissolved in 45.0 g of cyclohexane (C6H₁2), the freezing point of the solution is measured to be 6.5 °C. Calculate the molar mass of X. If you need any additional information on cyclohexane, use only what you find in the ALEKS Data resource. Also, be sure your answer has a unit symbol, and is rounded to 1 significant digit.

The boiling point of benzene, C6H6 , is 80.100 °C at 1 atmosphere. Kb (benzene)= 2.53C/m. In a laboratory experiment, students synthesized a new compound and found that when 14.93 grams of the compound were dissolved in 252.2 grams of benzene, the solution began to boil at 80.619 °C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound?   The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m. In a laboratory experiment, students synthesized a new compound and found that when 12.91 grams of the compound were dissolved in 271.5 grams of ethanol, the solution began to freeze at -117.406 °C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound?

As a scuba diver descends under water, the pressure increases. At a total air pressure of 2.69 atm and a temperature of 25.0 °C, what is the solubility of N2 in a diver's blood? [Use the value of the Henry's law constant k calculated in Part A, 6.26 x 10-4 mol/(L· atm).JAssume that the composition of the air in the tank is the same as on land and that all of the dissolved nitrogen remains in the blood. Express your answer with the appropriate units.

Glycerin 1C3H8O32 is a nonvolatile nonelectrolyte with a density of 1.26 g>mL at 25 °C. Calculate the vapor pressure at 25 °C of a solution made by adding 50.0 mL of glycerin to 500.0 mL of water. The vapor pressure of pure water at 25 °C is 23.8 torr (Appendix B), and its density is 1.00 g>mL.

A solution made by dissolving 150.0 g of an unknown compound in 425.0 mL of benzene to make a solution which has a freezing point 18.6 °C lower than that of pure benzene. Kf for benzene is 5.12 °C/m and the density of benzene is 0.877 g/mL.     What was the molality of the solution?   How many moles of the unknown compound were dissolved in the solution?   What is the molar mass of the unknown compound?

1 A certain liquid X has a normal freezing point of 0.40 °C and a freezing point depression constant K = 5.78 °C·kg⋅mol A solution is prepared by dissolving some glycine (C₂HÃNO₂) in 850. g of X. This solution freezes at −5.2 °C. Calculate the mass of C₂H²NO₂ that was dissolved. Be sure your answer is rounded to the correct number of significiant digits. 1 g | x10 S