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lat is the th CH,CH,OH + H,SO,→ CH,=CH, + H,0 OmL ethanol (MM: 46.07g/mol); ethylene (MM: 28.05); 30mL sulfuric acid 10 x 0.789g/mol = (7.89g x 1mol/46.07g) x (28.05g/1mol) = 4.80 g (L.R.) %3D 30 x 1.840g/mol = (55.2g x 1mol/98.08g) x (28.05/1mol) = 15.8 g %3D

lat is the th CH,CH,OH + H,SO,→ CH,=CH, + H,0 OmL ethanol (MM: 46.07g/mol); ethylene (MM: 28.05); 30mL sulfuric acid 10 x 0.789g/mol = (7.89g x 1mol/46.07g) x (28.05g/1mol) = 4.80 g (L.R.) %3D 30 x 1.840g/mol = (55.2g x 1mol/98.08g) x (28.05/1mol) = 15.8 g %3D

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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TOPIC: Preparation of Ethylene

Expound and explain the given answer to the question.

What is the theoretical yield of the given reaction? CH,CH,OH + H,SO, > CH,=CH, + H,0 10ml ethanol (MM: 46.07g/mol); ethylene (MM: 28.05); 30mL sulfuric acid 10 x 0.789g/mol = (7.89g x 1mol/46.07g) x (28.05g/1mol) = 4.80 g (L.R.) %3D 30 x 1.840g/mol = (55.2g x 1mol/98.08g) x (28.05/1mol) = 15.8 g
Transcribed Image Text:What is the theoretical yield of the given reaction? CH,CH,OH + H,SO, > CH,=CH, + H,0 10ml ethanol (MM: 46.07g/mol); ethylene (MM: 28.05); 30mL sulfuric acid 10 x 0.789g/mol = (7.89g x 1mol/46.07g) x (28.05g/1mol) = 4.80 g (L.R.) %3D 30 x 1.840g/mol = (55.2g x 1mol/98.08g) x (28.05/1mol) = 15.8 g
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