Last year at a local country club, 60% of the golfers were “full members”, 30% were “junior members”, and the remaining 10% were guests. In a sample of 400 golfers this year, 210 have been “full members”, 100 were “junior members’, and the remaining 90 were guests. At the 5% level of significance, does it appear the proportions have changed? Write all formulas and hypothesis

use a hypothesis test to determine if the proportions are statistically different. A recent survey showed that in a sample of 100 elementary school teachers, 15 were single. In a sample of 180high school teachers, 36 were single. Is the proportion of high school teachers who were single greater than theproportion of elementary teachers who were single? Use ΅ = 0.01.

A survey of Hoosiers found that 47%47% are Pacers fans, 54%54% are Colts fans, and 25%25% are Pacers fans but not Colts fans. What proportion of those surveyed are Colts fans but not Pacers fans?

Treat the dataset as your bag of peanut M&M’s (a simple random sample). Count the number of orange M&M’s and the total number of M&M’s in your bag. Then determine the proportion of your M&M’s that are orange. Number of orange M&M’s: 13 Total number of M&M’s: 65 Proportion of orange M&M’s: 0.2   Question below is according to this.

Please solve this question below. Thank you! 9. Challenge A bag contains 200 red and blue marbles. Three people each took samples of 25 marbles and noted the number of red marbles. Person A 17 red marbles out of 25 marbles Person B 12 red marbles out of 25 marbles Person C 20 red marbles out of 25 marbles a. Combine the samples to make one large sample. Use that sample to predict the number of red marbles in a similar bag that contains 300 marbles. b. Explain how having a fourth sample would make the estimate better.

A business sent out a survey to it's customers in two groups; one under 30 years old (group 1) and one over 30 years old (group 2). Customers were asked if they preferred to purchase items online or in store. Out of 300 customers under 30 (group 1), 180 said that they purchased online. Out of 300 customers over 30 (group 2), 170 said that they purchased online. Is there a difference in the population proportion who purchased online? The business wanted to test the hypothesis Ho: P2 P1 O versus Ha: P2 - P₁ does not equal Ö. What is the p-value? Use JMP and round the p-value to two decimal places.

A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below.      Age Group     Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000     (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…

A biologist is studying the composition of birds on a lake and counts 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons. From previous studies performed around the same time of the year, she expects 50% of the birds to be ducks, 23% to be geese, 12% to be cranes, 10% to be swans, and 5% to be herons. What are the expected and observed counts? Select one. Expected = 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons Observed = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons Expected = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons Observed 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons %3D Expected = 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons Observed = 55 ducks, 25 geese, 13 cranes, 11 swans, and 6 herons %3D %3D Expected = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons Observed = 61 ducks, 17 geese, 11 cranes, 15 swans, and 6 herons

A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below.      Age Group     Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000     (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…

A statistics teacher asked two different students, Lexie and Jennifer, to go to Wegmans and sample 30 shoppers each.  The population of interest for both people can be defined as, “People who shop at the Johnson City, NY Wegmans store”.  Here is what each person did to collect their sample:                    Lexie: She stood outside at the entrance to the store on 3 different days and times and surveyed every 15th person to walk by her.  She surveyed 10 people each time to get her 30.   Jennifer:  She went to Wegmans after her nursing shift first thing Wednesday morning to buy deodorant since she ran out.  When she was in the pharmacy area she surveyed all the people around her and then, to get up to 30 surveys, she went to the health food section and surveyed everyone she was there.     Identify at least 2 specific reasons why Lexie’s approach is more likely to give a representative sample.  Consider sources of bias, or types of shoppers who might be excluded by Jennifer’s approach.…