College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Part A A downward electric force of 9.0 N is exerted on a -9.5 µC charge. Find the magnitude of the electric field at the position of this charge. Express your answer to two significant figures and include the appropriate units. HA N E = 9.47 10 Droio e Anaanrs Ponuns Aneam • Previous 神 hp W hp 15 f6 f7 f8 f9 f10 f11 F12 insertarrow_forwardB3arrow_forwardPls help me with the following question pls and make sure 100 % of your answer is correct A charge q1�1 = 5.00 nCnC is placed at the origin of an xy��-coordinate system, and a charge q2�2 = -3.00 nCnC is placed on the positive x� axis at x=�= 4.00 cm Part A If a third charge q3�3 = 5.00 nCnC is now placed at the point x=�= 4.00 cm , y=�= 3.00 cmcm find the x� component of the total force exerted on this charge by the other two charges. Express your answer in newtons. ( I got this right, which was -> 7.19 x 10^-5 N) Part B Find the y� component of the total force exerted on this charge by the other two charges. Express your answer in newtons. ( I got this one wrong like the rest, here I got -> -14.624 x 10^-5N)Pls help me explain what could be wrong Part C Find the magnitude of this force. Express your answer in newtons.( I got this answer and it was wrong-> 16.30 x 10^-5N) Part D Find the direction of this force. Express your answer in degrees. (I got this…arrow_forward
- C) The lightning is formed when current starts to flow between the two spheres. Explain at least two different non obvious facts about what is going on inside and around these “lightning bolts”. If a direction is involved with your facts, give that direction.arrow_forwardA proton is placed in a uniform electric field of 2650 N/C. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Electron in a uniform field. Part B Calculate the proton's acceleration. Express your answer in meters per second squared. a = 2.5x10¹1 m/s² Submit Correct F a = Part C V = Previous Answers m 4.24×10-16 N 1.67×10-27 kg Calculate the proton's speed after 1.40 us in the field, assuming it starts from rest. Express your answer in meters per second. Π ΑΣΦ 4167.55 105 2.54 × 10¹¹ m/s² ● Submit Previous Answers Request Answer ? m/sarrow_forwardPart A An electron moving parallel to a uniform electric field increases its speed from 2.0x10' m/s to 4.0×10 m/s over a distance of 1.2 cm. What is the electric field strength? Express your answer with the appropriate units. HA E = Value Units Submit Request Answerarrow_forward
- Two 2.8 g point charges on 1.0-m-long threads repel each other after being equally charged, as shown in the figure. (Figure 1) Assume that 0 = 14°. Part A What is the charge q? Express your answer with the appropriate units. O q= 0.72 μÅ μC ?arrow_forwardI do not know how to solve the attached phyiscs question.arrow_forwardPart A Calculate the magnitude of the electric field at one corner of a square 2.42 m on a side if the other three corners are occupied by 6.75x10 C charges. Express your answer to three significant figures and include the appropriate units. ? E = Value Units Submit Request Answerarrow_forward
- In an effort to better understand the behavior of atomic systems, the Danish physicist Niels Bohr (1885-1962) introduced a simple model for the hydrogen atom. In the Bohr model, as it is known today, the electron is imagined to move in a circular orbit about a stationary proton. The force responsible for the electron's circular motion is the electric force of attraction between the electron and the proton. Part A Find the orbital radius for which the kinetic energy of the electron is 2.72 eV. (Note: 1 eV = 1 electron - volt 1.6 × 10-¹⁹ J.) VE ΑΣΦ r = Submit - Request Answer Ć = ? marrow_forwardA E The picture shows the field lines of a nonuniform electric field and five points A to E in the field. Consider the following statements. Which one is true? This electric field may be due to a negatively charged object located to the left. A positive point charge placed at point C will feel a stronger electric force than at point D. OThe electric field strengths at points B and C are the same because they are on the same field line. OThe electric field strengths at points A and D are both zero because there are no electric field lines on them. A negative point charge placed at point C will feel an electric force pointing to the right.arrow_forwardTwo 1.5 kg masses are 1.0 m apart (center to center) on a frictionless table. Each has + 9.6 μC of charge. For general problem-solving tips and strategies for this topic, you may want to view a Video Tutor Solution of Levitation. Part A What is the magnitude of the electric force on one of the masses? Express your answer with the appropriate units. F= Submit Part B Fit for Paredo for Part redo foart A reor Part A keyboard shortcuts for Part A help for Part A Value Request Answer Submit What is the initial acceleration of the mass if it is released and allowed to move? Express your answer with the appropriate units. for Rart for Part.Edo for Part redo folert 8 reor Part B keyboard shortcuts for Part 8 help for Part B Units Value Request Answer Unitsarrow_forward
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