Lagrange's polynomial p1 (1) that interpolates f(x)= at z = 2 and z = 5 is Select one: O a. pi(2) 3 0.25를 +0.04. 2-5 5-2" O b. P1 (r) = 0.25 + 0.04?. 2-5- I-5 5-2 Oc.pi(e) - 0.25를+0.04. I-2 I-5 O d. P1 (x) = 0.04 + 0.25 25 5-2 O e.pi(#) = 0.25 + 0.042 . 2-5 Of.p. (2) = 0.04+0.25음. 5 2

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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This question from numerical methods course.
Lagrange's polynomial p (z) that interpolates f(1) = at z = 2 and z = 5 is
Select one:
out of
O a. pn()- 0.25를 + 0.04.
O b.pi(a) -0.25를 +0.04금.
2-5
5-2
question
+ 0.04 2
2 5
5-2
O c. P:(#) = 0.25 + 0.04 2.
Z-2
Z-5
O d.pi(z) = 0.04 +0.25를.
Z- 2
5-2
2 5
O e. p1 (x) = 0.25 5=
+0.04 2 z
5-2
25
O f.p,(x) = 0.045 +0.25 -.
5-2
Transcribed Image Text:Lagrange's polynomial p (z) that interpolates f(1) = at z = 2 and z = 5 is Select one: out of O a. pn()- 0.25를 + 0.04. O b.pi(a) -0.25를 +0.04금. 2-5 5-2 question + 0.04 2 2 5 5-2 O c. P:(#) = 0.25 + 0.04 2. Z-2 Z-5 O d.pi(z) = 0.04 +0.25를. Z- 2 5-2 2 5 O e. p1 (x) = 0.25 5= +0.04 2 z 5-2 25 O f.p,(x) = 0.045 +0.25 -. 5-2
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