L/4 w L/2 L/A B A timber beam AB of length L and rectangular cross section carries a uniformly distributed load w and is supported as shown. (a) Show that the ratio Tom of the maximum values of the shearing and normal stresses in the beam is equal to 2h/L, where h and L are, respectively, the depth and the length of the beam. (b) Determine the depth h and the width b of the beam, knowing that L = 5 m, w = 8 kN/m, Tm = 1.08 MPa, and = 12 MPa.

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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L/4
D
L/2
LA
B
A timber beam AB of length L and rectangular cross section carries a
uniformly distributed load w and is supported as shown. (a) Show that
the ratio of the maximum values of the shearing and normal
stresses in the beam is equal to 2h/L, where h and L are, respectively,
the depth and the length of the beam. (b) Determine the depth h and
the width b of the beam, knowing that L = 5 m, w = 8 kN/m,
Tm = 1.08 MPa, and om = 12 MPa.
Transcribed Image Text:L/4 D L/2 LA B A timber beam AB of length L and rectangular cross section carries a uniformly distributed load w and is supported as shown. (a) Show that the ratio of the maximum values of the shearing and normal stresses in the beam is equal to 2h/L, where h and L are, respectively, the depth and the length of the beam. (b) Determine the depth h and the width b of the beam, knowing that L = 5 m, w = 8 kN/m, Tm = 1.08 MPa, and om = 12 MPa.
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