College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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**Problem Statement (L10)**

A single circular current-carrying loop with a radius of \(4.40 \times 10^{-2}\) meters is centered at the origin and carries a current of 2.71 amperes. The magnetic moment \(\mu\) of the loop points at an angle \(\theta = 27.0^\circ\) from the \(+y\)-axis, as shown in the diagram. A uniform, constant magnetic field \(B = 0.544\) teslas is applied in the \(+y\) direction.

**Question:** What is the magnitude of the torque that the magnetic field exerts on the current loop (in Newton-meters, N⋅m)?

---

**Diagram Explanation:**

The accompanying vector diagram illustrates the relationship between the magnetic moment \(\mu\), the magnetic field \(B\), and the angle \(\theta\):

- The vertical arrow labeled \(B\) represents the direction of the magnetic field, aligned with the \(+y\)-axis.
- The vector labeled \(\mu\) represents the magnetic moment of the loop and lies at an angle \(\theta\) (\(27.0^\circ\)) from the \(+y\)-axis.
- The loop’s orientation is indicated by a circle in the \(xy\)-plane at the origin.
- The coordinate axes (\(+x\) and \(+y\)) are also indicated for reference. 

---

**Solution Approach:**

To determine the magnitude of torque (\(\tau\)) exerted by the magnetic field on the current loop, we use the formula:

\[
\tau = \mu B \sin \theta
\]

where:
- \(\mu\) is the magnetic moment of the loop,
- \(B\) is the magnetic field strength,
- \(\theta\) is the angle between \(\mu\) and \(B\).

The magnetic moment \(\mu\) for a current loop is given by:

\[
\mu = I \cdot A
\]

where:
- \(I\) is the current,
- \(A\) is the area of the loop.

The area \(A\) of a circular loop is:

\[
A = \pi r^2
\]

Given values:
- Current \(I = 2.71\) A,
- Radius of the loop \(r = 4.
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Transcribed Image Text:**Problem Statement (L10)** A single circular current-carrying loop with a radius of \(4.40 \times 10^{-2}\) meters is centered at the origin and carries a current of 2.71 amperes. The magnetic moment \(\mu\) of the loop points at an angle \(\theta = 27.0^\circ\) from the \(+y\)-axis, as shown in the diagram. A uniform, constant magnetic field \(B = 0.544\) teslas is applied in the \(+y\) direction. **Question:** What is the magnitude of the torque that the magnetic field exerts on the current loop (in Newton-meters, N⋅m)? --- **Diagram Explanation:** The accompanying vector diagram illustrates the relationship between the magnetic moment \(\mu\), the magnetic field \(B\), and the angle \(\theta\): - The vertical arrow labeled \(B\) represents the direction of the magnetic field, aligned with the \(+y\)-axis. - The vector labeled \(\mu\) represents the magnetic moment of the loop and lies at an angle \(\theta\) (\(27.0^\circ\)) from the \(+y\)-axis. - The loop’s orientation is indicated by a circle in the \(xy\)-plane at the origin. - The coordinate axes (\(+x\) and \(+y\)) are also indicated for reference. --- **Solution Approach:** To determine the magnitude of torque (\(\tau\)) exerted by the magnetic field on the current loop, we use the formula: \[ \tau = \mu B \sin \theta \] where: - \(\mu\) is the magnetic moment of the loop, - \(B\) is the magnetic field strength, - \(\theta\) is the angle between \(\mu\) and \(B\). The magnetic moment \(\mu\) for a current loop is given by: \[ \mu = I \cdot A \] where: - \(I\) is the current, - \(A\) is the area of the loop. The area \(A\) of a circular loop is: \[ A = \pi r^2 \] Given values: - Current \(I = 2.71\) A, - Radius of the loop \(r = 4.
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