k/s T/C T/K 1/T (K) Ink 0.00018 477 750 0.00133 -8.62 In(k) vs 1/T 0.00270 523 796 0.00126 -5.91 0.03000 S77 850 0.00118 -3.51 0.26000 623 896 0.00112-1.35 -1 -2 Slope 33105 K Intercept 35.SS -7 -10 0.00110 0.00115 0.00120 0.00125 0.00130 0.00135 א ז/ The equation of the line is y= -33105x + 35.55 a) What are the units on the slope and intercept? b) What is the k at 555 °C? c) At what temperature is the k=.00047 s-1?

In a lab investigation, a student is asked to crush and measure 1 g of sulfur from a larger solid block. The student understands that although the mass of the sample is changing, the melting point will remain the same because he/she knows that ___.

25.345 mcg/ml is converted to kg/cm^3?

Missing molar conductivity Given: Conductivity: 281 us x cm^-1 (microseconds/cm) Concentration of solution: 0.05555555556 M (mol/lit) Basically, molar conductivity = conductivity/concentration, but what I'm not sure of is the proper unit for the answer molar conductivity and if it will require the given conductivity to be converted to seconds and meter (or not? I'm not sure cause i've been seeing S⋅m2⋅mol−1 in the internet as the unit for molar conductivity)

smilify all your solutions

A nursing floor requires half liter of 50% isopropyl alcohol. How many millimeters of 70% isopropyl alcohol will be needed for compounding this order?

12.4 mL of a urine sample has a mass of 0.13 g. What is the specific gravity of the sample. Report correct units (if any). 0.010 95 g/mL 0.010 g/mL 0 95

In a suspension the substances are mixed at a: Ophysical level O atomic level O both physical and chemical level chemical level

A student measured the melting point range of an unknown solid to be 81.9 to 82.3 degrees celsius. a) Is the compound pure? b) Can you identify the compound from Table 2.2? c) If yes, what is the compound? Table 2.2: Solid - Melting Point (Celsius) Benzoic Acid - 122 Acentanilide - 114 Acetamide - 82 Biphenyl - 71 p-Dimethoxybenzene - 59 p-Dichlorobenzene - 54 Benzophenone - 48

please answer using the diagram given, thanks