k = 100 N/m m = 0.50 kg Ho.20 m -1.00 m

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A block with mass 0.50 kg is forced against a horizontal
spring of negligible mass, compressing the spring a distance of 0.20 m
(Fig. ). When released, the block moves on a horizontal tabletop
for 1.00 m before coming to rest. The force constant k is 100 N>m.
What is the coefficient of kinetic friction mk between the block and the
tabletop? 

k = 100 N/m
m = 0.50 kg
Ho.20 m
-1.00 m
Transcribed Image Text:k = 100 N/m m = 0.50 kg Ho.20 m -1.00 m
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