JXY (x, y) 15y, Find fy (y). calculate the marginal density functions of the random vector.
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- Let X be a continuous random variable with probability density function 1 -1sxs1 fx(x) = { 2 0 else The value of P(X´ > 2) is Select one: а. 1 b. 1/2 c. 0.707 d. 0.293 е. ОThe density function, ху fy(x, y) = f(x) =9 0, 0Let X and Y be two independent random variables with respective probability density functions (pdfs) 0, x 0 ue-HY, y > 0 The expression for P(X > 1, Y < 1) is Select one: о (1-е ^) . е и O ed. e H O (1 - e ") · e-A O A. µ.e-de 4Two non-negative random variables X and Y have a joint density function f(x, y) = re-*v +1) x > 0, y > 0 Find the correlation coefficient.X is a uniform random variable over the interval (3, 5). Find the density function of X for the interval (3, 5)Let (X,Y) be a two-dimensional random variable with the density function below. So P(X>1/2 | Y>1)=P(X>1/2)? **continuation on image** **caso contrário = otherwise**Let X be a uniform random variable on the interval (-3,3) and let Y = X^2 A) find E(Y). B) find the probability density function of Y• Find the density of Z = (X+ Y)2, where X and Y are independent uniform random variables over (-1, +1).Let X and Y be two continuous random variables having joint pdffX,Y (x, y) = (1 + XY)/4, −1 ≤x ≤1, −1 ≤y ≤1.Show that X ^2 and Y ^2 are independent.The density function of two random variables X and Y is ,-2(x+y) fx,r (x, y) =u(x)u(y)4e¯¾x*y) X,Y Find the mean value of the function e-*+),The joint probability density function of two random variables X and Y is f(x, y)= 4xye^-(x^2+y^2). Find P(1<x<=2, 1<Y<=2)Suppose that two continuous random variables X and Y have joint probability density function fxy = 1sxs2,0sy<3 elsewhere Find the strength of the relationship and interpret the findings.SEE MORE QUESTIONS
