Just solve 65 000(0.08 + 200 - 0.004) / (800 x 300

Q: 10 = 35(1.3)* for x using logs. X =

A: Given query is to find the value of x.

Q: Solve: 1/(x + 2) = 4/(x2 - 4) - 1/(x - 2) .

A: 1. Take LCM in RHS. 2. Do cross multiplication and solve it.

Q: Solve                 2   =   X-500/ 85

A: Firstly, we add 500/85 on both sides  and then by adding 2+500/85, we get the required result.

Q: (7x10^5)+(9x10^3) Show all your work. Keep numbers as a power of 10. Do not expand out to standard…

A: Given query is to perform the addition.

Q: 4 x 105) / (-1.52 x 109)

A: It is from simplification topic

Q: Solve for x: 7/15 = x-3/100

A:

Q: 3509ft is how many kilometers?  Give the first four digits of your answer.

A: Simple value converter problem....

Q: Solve for w: 200(1.05)^w = 15,780

A: The given equation is 2001.05w=15,780.

Q: x^2 = 0.25  solving by using inspection

A: By inspection" means "by happening to think of a solution that works", which is allowed to include…

Q: Solve (-9x)4/3 = 81.

A: To solve the given expression

Q: 320(1.6)* for x using logs. x =

A: We need to find value of x.

Q: solution r^3 = 36r

A: The given equation is a third degree equation. So it has 3 solutions.

Q: Solve :  -(2/3)x = (3/4

A:

Q: Solve for X 60 2. 500,000 = (7+ 12.

A: Given query is to solve 500000=7+x1260

Q: Solve: 5ᴫ/4 = 2ᴫx.

A: According to the question, we have to solve the expression 5π4=2πx. As we have to solve the equation…

Q: Please fast solve  -1/2n +(- 1/2n

A: Solution is done in step 2

Q: solve 8/9x - 1/3= 5/6x

A:

Q: Solve  x - 0.001x = 9990

A: Given expression is: x-0.001x=9990

Q: If 2 = 100.301 and 3 =100477, solve 10* = 12 for x.

A:

Q: $5x = $10,000 + $3x + 0.10 * ($10,000 + $3x). solve for x

A: The objective of the question is to solve for the variable 'x' in the given equation.

Q: 4. Solve the equation: 2(9)* = 162 a. x = 2 b. x = 9 C. x = 3 d. x = 6

A:

Q: Solve for X: (x+4)^2=25

A: To solve for .

Q: 2 = 1 +| Month:

A: To solve 1+1

Q: 15^2=(2.6047^2)+b^2   Solve for b.

A: If , then .