Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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9 Collig Notes (1).pdf
A ALEKS - Jeneen Abdelre x
M Mathway Algebra Prol X
Gmolar mass of zinc chle x
Launch Meeting-Zoom x
www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-lix5uFZIVj2iEJjQd1WoxT77ErtzZpGbzESWhuQ5KnLFF-AdqJckJ3tzP4DtHEOm2H4pGXeoGQgUw9Q Lcoo6TW. *
G 0.16kg to g-Google Se x +
O GASES, LIQUIDS, AND SOLIDS
Using the Kf and Kb equations with electrolytes
Jeneen v
A certain liquid X has a normal boiling point of 120.70 °C and a bolling point elevation constant K,=2.07 °C-kg mol .Calculate the bolling point of a solutlon
made of 98.6g of iron(III) chloride (FeCl,) dissolved In 800. g of X.
Round you answer to 5 significant digits.
do
°C
x10
の
2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy | Accessibility
1 8:40
Check
Explanation
M 9
hp
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Transcribed Image Text:9 Collig Notes (1).pdf A ALEKS - Jeneen Abdelre x M Mathway Algebra Prol X Gmolar mass of zinc chle x Launch Meeting-Zoom x www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-lix5uFZIVj2iEJjQd1WoxT77ErtzZpGbzESWhuQ5KnLFF-AdqJckJ3tzP4DtHEOm2H4pGXeoGQgUw9Q Lcoo6TW. * G 0.16kg to g-Google Se x + O GASES, LIQUIDS, AND SOLIDS Using the Kf and Kb equations with electrolytes Jeneen v A certain liquid X has a normal boiling point of 120.70 °C and a bolling point elevation constant K,=2.07 °C-kg mol .Calculate the bolling point of a solutlon made of 98.6g of iron(III) chloride (FeCl,) dissolved In 800. g of X. Round you answer to 5 significant digits. do °C x10 の 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy | Accessibility 1 8:40 Check Explanation M 9 hp
Expert Solution
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Step 1

Given : Normal boiling point of liquid X = 120.70 oC

Mass of solvent i.e liquid X = 800 g = 0.800 Kg                                       (since 1 Kg = 1000 g)

And Mass of solute i.e FeCl3 = 98.6 g

Molar mass of FeCl3 = Atomic mass of Fe + Atomic mass of Cl X 3 = 55.845 + 35.5 X 3 = 162.345 g/mol.

Since mass = moles X molar mass

=> 98.6 = moles of FeCl3 X 162.345 

=> Moles of FeCl3 = 0.60735 mol approx.

 

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