java wirte a method that given an integer array, computes and returns an integer x. the starting value of x is equal to the array length. for every odd element in the array, substract it from x, and for every even element in the array add it to x . Example: Array: [13,2,3,4,5] Result: x=5-13+2-3+4-5 x= -10
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in java wirte a method that given an integer array, computes and returns an integer x. the starting value of x is equal to the array length.
for every odd element in the array, substract it from x, and for every even element in the array add it to x .
Example:
Array: [13,2,3,4,5]
Result: x=5-13+2-3+4-5
x= -10
Step by step
Solved in 2 steps with 1 images
- Java programming language Write a method to sum the even numbers and multiplication the odd positive numbers in the array shown below and then test it: array= {2, 5, 16, -89, 76, -60, -35, -12, 5, 41, -50}.in java write a method that given an integer array, computes and returns the sum of all negative numbers in the array. Example: array: 13, -2, 3, -4, -5 result: x= -2 -4 -5; x= -11PLEASE SOLVE IN JAVA without using arrays list just simple array FAST PLEASE Write a java method that receives two arrays of integers called arr1 and arr2 and then returns the number of rotations to the left or to the right so that arr1 and arr2 becomes the same. if not possible the method returns your student ID number.
- Java programming Write a method that takes an array of integers as a parameter. The method should return the occurrence of the even numbers in the passed arrayJAVA PROGRAM Use a one-dimensional array to solve the following problem: A company pays its salespeople on a commission basis. The salespeople receive $200 per week plus 9% of their gross sales for that week. For example, a salesperson who grosses $5000 in sales in a week receives $200 plus 9% of $5000, or a total of $650. Write an application (using an array of counters) that determines how many of the salespeople earned salaries in each of the following ranges (assume that each salesperson’s salary is truncated to an integer amount): $200–299 $300–399 $400–499 $500–599 $600–699 $700–799 $800–899 $900–999 $1000 and over Summarize the results in tabular format. Please Explain Step by Step the logic of this program. THANK YOU AND GODBLESS BARTLEBY EXPERTS !Java Programming : At a fun fair, a street vendor is selling different colours of balloons. He sells N number of different colours of balloons (B[]). The task is to find the colour (odd) of the balloon which is present odd number of times in the bunch of balloons. Note: If there is more than one colour which is odd in number, then the first colour in the array which is present odd number of times is displayed. The colours of the balloons can all be either upper case or lower case in the array. If all the inputs are even in number, display the message 'All are even'. Example 1: 7 -> Value of N [r,g,b,b,g,y,y] -> B[] Elements B[0] to B[N-1], where each input element is separated by new line. Output: r -> [r,g,b,b,g,y.y] →> 'r' colour balloon is present odd number of times in the bunch. Explanation: From the input array above: r: 1 balloon g: 2 balloons b: 2 balloons y: 2 balloons Hence, r is only the balloon which is odd in number.
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- in java Integer numElements is read from input, representing the number of integers to be read next. Then, the remaining integers are read and stored into array valuesArray. For each element in valuesArray that is divisible by 9, assign the element with the element's current value plus 1. Ex: If the input is: 3 81 99 30 then the output is: Original values: 81 99 30 New values: 82 100 30 Note: (x % 9 == 0) returns true if x is divisible by 9. 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 for (i=0; i<valuesArray.length; ++i) { valuesArray[i] =scnr.nextInt(); } System.out.print("Original values: "); for (i=0; i<valuesArray.length; ++i) { System.out.print(valuesArray[i] +" "); } System.out.println(); /* Your code goes here */ System.out.print("New values: "); for (i=0; i<valuesArray.length; ++i) { System.out.print(valuesArray[i] +" "); } System.out.println(); } }URGENT JAVA Write a Java method that takes two 2 dimensional int arrays (a and b) and a 2 dimensional boolean array (c) where all three arrays have the same size. Your method should return an array (result) such that, if a partic- ular element in c is true, then the corresponding (same indexed) element in result must be the multiplication of the the corresponding elements of a and b. If the element in c is false, then the the corresponding element in result must be the negative of multiplication of the the corresponding element in a and b. For example ifa = {{1,2,3},{4,5}},b = {{1,2,1},{0,2}} andc = {{true,false,true},{false,true}}, then the result should be result={{1, -4, 3}{0, 10}}.java getDup accepts an array and returns an int. If there is any element is duplicated, the method counts how many of those present in the array. Example : getDup(["1","2","aa"',"1"]) returns:2 ("1" is duplicated and there are two "1"s so return is 2) class Main { public static int getDup(String[] r) { } public static void main(String[] args) { Scanner in = new Scanner(System.in); String [] strs = new String[in.nextInt()]; for(int i=0; i < strs.length; i++) { strs[i] = in.next(); } System.out.println(getDup(strs)); } } hint: you will need a nested array the will run on the array we get from the method argument. inside the nested loop you will need to check if the main array element is equal to the current