College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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The formulas are in the picture. (The acceleration due to gravity is 9.8 m/s^2 because the formulas are already negative.) 

Please explain it in an easy to understand way and show what formulas you use too. 

Jason jumps his motorcycle off a 50m tall cliff. How fast does he have to go to land at his target 90 m from the base of the cliff? (assume no air resistance)


A football is kicked at a 37 degree angle at 20 m/s. Calculate: a) max height b) time in the air c) horizontal range d) velocity at max height e) acceleration at max height. (Assume no air resistance.)

Projectile Motion, Constant Accel. Formulas
X components (horizontal):
projectile:
Vx =Vx0 + a,t
X = X, + Vxot + ½ a,t?
V =Vx0
x = X, + Vxot
v,? = V,0
%D
v,? = V,0²
2
+ 2a,(x-Xo)
хо
Y components (vertical):
projectile:
Vy = Vyo - gt
y = yo + Vyot - ½ gt?
Vy = Vyo+ ayt
y = Yo + Vyot + ½ a,t²
'yot + ½ a,t?
v,? = v,² + 2a,(y-y.)
v, = v,² -
2g(y-yo)
= V.
= V.
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Transcribed Image Text:Projectile Motion, Constant Accel. Formulas X components (horizontal): projectile: Vx =Vx0 + a,t X = X, + Vxot + ½ a,t? V =Vx0 x = X, + Vxot v,? = V,0 %D v,? = V,0² 2 + 2a,(x-Xo) хо Y components (vertical): projectile: Vy = Vyo - gt y = yo + Vyot - ½ gt? Vy = Vyo+ ayt y = Yo + Vyot + ½ a,t² 'yot + ½ a,t? v,? = v,² + 2a,(y-y.) v, = v,² - 2g(y-yo) = V. = V.
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