Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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![## Educational Content: Understanding Python List Operations
### Exercise: Analyze Code Fragments
For each of the following code fragments (each box is a separate code fragment), determine what the program outputs or write "error" if it would crash or has a syntax error that prevents it from running.
---
#### Code Fragment 1:
```python
items = [2, 4, 5, 6]
items.insert(1, 7)
print(items)
```
- **Explanation:**
- The list `items` initially contains `[2, 4, 5, 6]`.
- `items.insert(1, 7)` inserts the number `7` at index `1`.
- The list becomes `[2, 7, 4, 5, 6]`.
- The `print(items)` statement outputs: **[2, 7, 4, 5, 6]**.
---
#### Code Fragment 2:
```python
items = [3, 4, 5, 6]
items = items.reverse()
print(items)
items = [3, 4, 5, 6]
items.reverse()
print(items)
```
- **Explanation:**
- The first part attempts to assign the result of `items.reverse()` to `items`. However, `reverse()` performs an in-place reversal and returns `None`. So `items` becomes `None`, causing the next line `print(items)` to output: **None**.
- The second part correctly uses `reverse()` in place, so the list `[3, 4, 5, 6]` becomes `[6, 5, 4, 3]`.
- The `print(items)` statement outputs: **[6, 5, 4, 3]**.
---
#### Code Fragment 3:
```python
items = [2, 3, 4, 5, 6]
print(items.index(4))
items.remove(4)
print(items)
```
- **Explanation:**
- `print(items.index(4))` finds the index of `4`, which is `2`. It outputs: **2**.
- `items.remove(4)` removes the first occurrence of `4` from the list.
- The list becomes `[2, 3, 5, 6]`.
- The `print(items)` statement](https://content.bartleby.com/qna-images/question/2d13e652-9219-41ff-a3a4-ec9d64bc6f59/ba9e07c0-bd79-401f-bfa1-334c2357019b/4gie1a_processed.jpeg)
Transcribed Image Text:## Educational Content: Understanding Python List Operations
### Exercise: Analyze Code Fragments
For each of the following code fragments (each box is a separate code fragment), determine what the program outputs or write "error" if it would crash or has a syntax error that prevents it from running.
---
#### Code Fragment 1:
```python
items = [2, 4, 5, 6]
items.insert(1, 7)
print(items)
```
- **Explanation:**
- The list `items` initially contains `[2, 4, 5, 6]`.
- `items.insert(1, 7)` inserts the number `7` at index `1`.
- The list becomes `[2, 7, 4, 5, 6]`.
- The `print(items)` statement outputs: **[2, 7, 4, 5, 6]**.
---
#### Code Fragment 2:
```python
items = [3, 4, 5, 6]
items = items.reverse()
print(items)
items = [3, 4, 5, 6]
items.reverse()
print(items)
```
- **Explanation:**
- The first part attempts to assign the result of `items.reverse()` to `items`. However, `reverse()` performs an in-place reversal and returns `None`. So `items` becomes `None`, causing the next line `print(items)` to output: **None**.
- The second part correctly uses `reverse()` in place, so the list `[3, 4, 5, 6]` becomes `[6, 5, 4, 3]`.
- The `print(items)` statement outputs: **[6, 5, 4, 3]**.
---
#### Code Fragment 3:
```python
items = [2, 3, 4, 5, 6]
print(items.index(4))
items.remove(4)
print(items)
```
- **Explanation:**
- `print(items.index(4))` finds the index of `4`, which is `2`. It outputs: **2**.
- `items.remove(4)` removes the first occurrence of `4` from the list.
- The list becomes `[2, 3, 5, 6]`.
- The `print(items)` statement
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