ite a C++ program to count total number of even and odd elements in an a

Convert C/C++ code to MIPS Code

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C++ Program #include <string>using std::string; /*** Problem 1: Simple strings & loops** Given a string and an int n, create a new string * made of the first n characters of the original * string, followed by the first n-1 characters of * the original string, and so on. You may assume * that n is between 0 and the length of the string, * inclusive (i.e. n >= 0 and n <= str.length())* * Some examples:* "Chocolate", 4 -> "ChocChoChC"* "Chocolate", 3 -> "ChoChC"* "Ice Cream", 2 -> "IcI" */string decreasing(const string& str, int n){string result = "not done"; // Add your code herereturn result;} /*** Problem 2: Intermediate Strings & Loops** Given an input string, count the number of words ending * in 'y' or 'z' -so the 'y' in "heavy" and the 'z' in "fez" * count, but not the 'y' in "yellow". Make sure that your * comparison is not case sensitive. We'll say that a y * or z is at the end of a word if there is not an alphabetic * letter immediately following…