It takes an average of 10.4 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will increase if the patient is immediately told the truth about the injury. The EMT randomly selected 67 injured patients to immediately tell the truth about the injury and noticed that they averaged 10.8 minutes for their blood to begin clotting after their injury. Their standard deviation was 2.94 minutes. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: pv= 10.4 H: pv 1.5 > c. The test statistic t v 1.114 (please show your answer to 3 decimal places.) d. The p-value = 0.0500 (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should accept g. Thus, the final conclusion is that ... v the null hypothesis. O The data suggest that the population mean is not significantly greater than 10.4 at a = 0.05, so there is statistically insignificant evidence to conclude that the population mean time for blood to begin clotting after an injury if the patient is told the truth immediately is greater than 10.4. O The data suggest the population mean is not significantly greater than 10.4 at a = 0.05, so there is statistically significant evidence to conclude that the population mean time for blood to begin clotting after an injury if the patient is told the truth immediately is equal to 10.4. O The data suggest the populaton mean is significantly greater than 10.4 at a = 0.05, so there is statistically significant evidence to conclude that the population mean time for blood to begin clotting after an injury if the patient is told the truth immediately is greater than 10.4.

The scores on a test are normally distributed with a mean of 150 and a standard deviation of 30. Find the score that is 2 1/2 standard deviations above the mean.

Dr. Shoals predicts that people who walk a mile in moderately high heels and very high heels will differ in their levels of reported back pain. 27 participants walk in 4-inch heels and then 2.5-inch heels. He calculates the standard deviation of the difference scores and finds sD = 3.37. What is the standard error of the difference for difference scores?

The average age of senators in the 108th Congress was 62 years. If the standard deviation was 12.5 years, find the z-scores corresponding to the oldest and youngest senators of age 86 and 46. Round z scores to two decimal places.

The average triglyceride level of adult males is 126 milligrams per deciliter. You want to determine whether the true mean male triglyceride level is more than the average. You decide to pull a random sample of eight adult males and measure their triglyceride level. You find the sample mean is 127.9 milligrams per deciliter and the standard deviation is 4.12 milligrams per deciliter. What are the test statistic and the p-value? O The test statistic is 1.9 and the p-value is 0.1174. O The test statistic is 0.1174 and the p-value is 1.9. O The test statistic is 1.46 and the p-value is 1.30. O The test statistic is 0.1174 and the p-value is 1.30. O The test statistic is 1.30 and the p-value is 0.1167.

State two ways the standard deviation differs from the average deviation.

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A psychologist created a questionnaire to assess people's aggression. Assume that the questionnaire responses are regularly distributed with a standard deviation of 100. Assume that 15% of the scores are higher than 700. Determine the mean of the score distribution. Calculate your intermediate results to at least four decimal places. Round your answer to the nearest decimal point.

It takes an average of 9.1 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will decline if the patient is immediately told the truth about the injury. The EMT randomly selected 49 injured patients to immediately tell the truth about the injury and noticed that they averaged 8 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.31 minutes. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Hint: Ho: ? H₁: ? Select an answer Select an answer C c. The test statistic? is -2.326. Enter it here d. The p-value is 0.0121364015. Enter it here e. The p-value is ? a f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) The data suggest the populaton mean is…

The scores on a standardized test are normally distributed with a mean of 95 and standard deviation of 25. What test score is 0.3 standard deviations below the mean?