It is often necessary to do calculations using scientific notation when working chemistry problems. For practice, perform each of the following calculations. (7.46 × 106) (1.00 × 10-8) 2.58 x 10 3.90 x 10 (7.46 × 106) (3.90 × 10¹) (7.11 × 105) (9.70 × 10-4) x

Convert 2.1 m^2 to cm^2 Convert 3.0 m/s^2 to km/h^2

Use the References to access important values if needed for this question. It is often necessary to do calculations using scientific notation when working chemistry problems. For practice, perform each of the following calculations. 3.17 × 105 +7.18 × 104 = X 8.97 × 10 +3.17 × 105 X X 5.85 × 104 [References] 2.00 × 10-5 (3.17×105) (7.18 × 10- X

The first one

Can you show your math? 10^-6 times 500 = .0005 and that divided by 1.07 is not 0.0035?

When you perform the following operations, how many significant figures should your answer have? (2.000 cm^ 3 *15.35 g/cm^ 3 )+200.1 g=

(282.7×105)−(1.100×103)]×2.8990 Express your answer to the appropriate number of significant digits.

In 1999, scientists discovered a new class of black holes with masses 100 to 10,000 times the mass of our sun, but occupying less space than our moon. Suppose that one of these black holes has a mass of 1×10^3 suns and a radius equal to one-half the radius of our moon. What is its density in grams per cubic centimeter? The mass of the sun is 2.0×10^30 kg and the radius of the moon is 2.16×10^3 mi (Volume of a sphere =4/3πr^3)

Use the References to access important values if needed for this question. It is often necessary to do calculations using scientific notation when working chemistry problems. For practice, perform each of the following calculations. (3.10 × 10-5) (1.00 × 10-8) 10-8)=[ 3.55 × 104 2.75 x 10-4 7.55 × 105 (3.10 × 10-5) (2.75 × 10-4) 3.55 × 104

Use Correct significant digits please