It is desired to prepare a saturated methanol vapor-air mixture containing 3% methanol by bringing dry air in contact with methanol kept in a container at 100 kPa. What temperature (in K) should be used to achieve the desired composition? The vapor pressure of methanol (in kPa) is given by the Antoine equation ln P = 16.5725 – [3626.25/ (T,K – 34.29)]

A stream of liquid water at a rate of 8 lit/s with a stream of methanol and ethanol mixture (contains 25 mol% methanol) are fed to continues evaporator. Another stream of methanol at a molar flow rate of 1 that of the alcohol mixture stream is fed to the same unit. If the liquids are evaporated totally and the produced vapor stream contains (0.1*1) mol% of water at a pressure of 28 psi and 220 °F, calculate: 1- The flow rate and composition of all streams in a molar, mass, and volumetric basis 2- The average molecular mass of all streams The Specific gravity of methanol is 0.762 and that of ethanol is 0.789 while the density of vapors can be estimated as: p=p*Mw/R*T where R-0.082 atm.m'kmol.K.

Use the information about three gases, with the properties below to answer the following questions. Nitrogen (N2) Oxygen (02) Argon (Ar) 93.0 °C 83.0 °C 73.0 °C M (kg/kmol) 28 32 40 Use the van der Waals equation of state and mixing rules to calculate the temperature where 100 kmol of a mixture of argon (10 mol%), nitrogen (45 mol%) and oxygen (45 mol %) would occupy 46.27 m³, at a pressure of 6.28 MPa. It is known that the van der Waals constant for nitrogen are a=1.370 atm(m³/kmol)² and b=0.0387 m³/kmol, and for oxygen are a=1.382 atm(m³/kmol)² and b=0.03186 m³/kmol. 63.0 °C Tc (K) 126.2 154.6 150.8 Pc (atm) 33.5 49.8 48 @ 0.04 0.021 -0.004

How did this arrive from that value? Because when I tried to solve it manually, the value I get is 20.83...