Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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It doesn't seem as if ICMPv6 Neighbor Solicitations are transmitted as a broadcast.
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- The Neighbor Solicitations are sent out as a multicast rather than a single broadcast; nevertheless, the question is: why is this??arrow_forwardIt doesn't seem as if ICMPv6 Neighbor Solicitations are transmitted as a broadcast.arrow_forwardGive some particular examples of how Dirty and Phantom both behave in ways that are against the rules.arrow_forward
- please please answer asaparrow_forwardHttps is a protocol used to secure websites from being tampered with by other parties without proper authorization. it bridges the gap between sender and receiver.Using protocols like secure socket layer/TLS, HTTPS encrypts data sent over the internet, making it unreadable to anybody who shouldn't have it.This prevents a "man in the middle" assault on the system.Such assaults intercept messages before they reach their intended recipient.It then transmits the revised information to the user.It guarantees the server's authenticity, too.arrow_forwardWeirdly, ICMPv6 Neighbor Solicitations seem to be sent out as a multicast rather than a broadcast.arrow_forward
- It doesn't seem as if ICMPv6 Neighbor Solicitations are transmitted as a broadcast.arrow_forwardNeedham and Schroeder suggest the following variant of their protocol: 1. Alice → Bob : Alice 2. Bob→ Alice: {Alice rand3}kBob 3. Alice → Cathy : {Alice Bob rand₁|{Alice rand3}kBob} 4. Cathy → Alice: {Alice Bob rand₁|ksession|{Alice rand3|ksession}KBob}KAlice 5. Alice → Bob: {Alice rand3|ksession}kBob 6. Bob→ Alice: {rand2}ksession 7. Alice → Bob: {rand2-1}ksession Show that this protocol solves the problem of replay as a result of stolen session keys. Hint: Consider two cases, one in which the attacker does not send an initial message to Bob and one in which the attacker does.arrow_forward1. If the values of user tool frame UT[2] is (0, 0, 0, 0, 0, 0) in the robot system, then UT[2] (a) is not activated in the robot system (b) cannot be used in recording robot point P[n] (c) coincides with default TCP frame (Def-TCP) of the robot in the robot system (d) coincides with robot world frame R in the robot system 2. A frame transformation is given as 4T; = (X,Y,Z,W,P, R) = (0,0,0, –90, 0, 90). The corresponding graphical representation of the given frame transformation is (a) (b) y yarrow_forward
- Write Algorithm for Auxiliary methods for the lockstep protocol.arrow_forwardThe token bucket algorithm is a popular method for traffic shaping. A computer uses a token bucket with acapacity of 400 megabytes (MB) and a rate of 10 MB/sec. The computer continuously generates20 MB/sec for transmission from time 0. Assume the bucket’s water level is 200 MB at time 0.1a. How long will it take to send 1000 MB? Show the steps.1b. Draw a figure showing how the bucket’s water level evolvesarrow_forwardICMPv6 Neighbor Solicitations seem to be transmitted as a multicast rather than a broadcast, although this behavior makes no sense.arrow_forward
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