it amount deposited today d grow to $100,000 in 10 y

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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### Compound Interest Calculations

#### Example Question:

6. What amount deposited today in an account paying 4% compounded semiannually would grow to $100,000 in 10 years? 

This type of question involves calculating the present value needed to achieve a future value with compound interest. We'll use the formula for compound interest to solve this problem. 

#### Formula:

\[ P = \frac{A}{(1 + \frac{r}{n})^{nt}} \]

Where:
- \( P \) = principal amount (initial deposit)
- \( A \) = amount of money accumulated after n years, including interest.
- \( r \) = annual interest rate (decimal)
- \( n \) = number of times the interest is compounded per year
- \( t \) = number of years the money is invested or borrowed for

In this scenario:
- \( A = \$100,000 \)
- \( r = 0.04 \) (4% annual interest rate)
- \( n = 2 \) (compounded semiannually)
- \( t = 10 \) years

Plugging in the values:

\[ P = \frac{100,000}{(1 + \frac{0.04}{2})^{2 \times 10}} \]

Run the calculations to find the initial deposit amount needed for the desired future value.
Transcribed Image Text:### Compound Interest Calculations #### Example Question: 6. What amount deposited today in an account paying 4% compounded semiannually would grow to $100,000 in 10 years? This type of question involves calculating the present value needed to achieve a future value with compound interest. We'll use the formula for compound interest to solve this problem. #### Formula: \[ P = \frac{A}{(1 + \frac{r}{n})^{nt}} \] Where: - \( P \) = principal amount (initial deposit) - \( A \) = amount of money accumulated after n years, including interest. - \( r \) = annual interest rate (decimal) - \( n \) = number of times the interest is compounded per year - \( t \) = number of years the money is invested or borrowed for In this scenario: - \( A = \$100,000 \) - \( r = 0.04 \) (4% annual interest rate) - \( n = 2 \) (compounded semiannually) - \( t = 10 \) years Plugging in the values: \[ P = \frac{100,000}{(1 + \frac{0.04}{2})^{2 \times 10}} \] Run the calculations to find the initial deposit amount needed for the desired future value.
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