is The Inverse Laplace Transform of F(s) s+2 s− 1)(s +3)² = (a) [be² - 3 t 16 (b) [iget - 3 16 e-3t+te-3tu(t) e-3t+te-3t] u(t) 3 (c) [iget + fe-3t] u(t) 3 16 (d) [ige² + te-3t] u(t) 3 et 16 (e) none of the above

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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Need help finding the inverse Laplace Transform of the function.

is
The Inverse Laplace Transform of
F(s) =
s+2
(s− 1)(s +3)²
(a)
[et-e-3t+te-3tu(t)
16e
16e
(b) [et — e-³t + te-3t] u(t)
3
3t
16
(c) [iget + fe-³t] u(t)
3
1
16
(d) [e² + te−3t] u(t)
3 t
16
(e) none of the above
Transcribed Image Text:is The Inverse Laplace Transform of F(s) = s+2 (s− 1)(s +3)² (a) [et-e-3t+te-3tu(t) 16e 16e (b) [et — e-³t + te-3t] u(t) 3 3t 16 (c) [iget + fe-³t] u(t) 3 1 16 (d) [e² + te−3t] u(t) 3 t 16 (e) none of the above
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