Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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Related questions

Question

Is |3x-1| a function?

 

The image contains a portion of a math problem and its solution explaining a function evaluation. 

### Function Evaluation

#### Problem:
Evaluate the function \( f(x) \) at \( x = -5 \).

#### Solution:
\[ 
c) \quad f(-5) = 
\]

Calculating:

\[ 
f(-5) = (-5)^2 - 2 
\]

\[ 
f(-5) = 25 - 2 
\]

\[ 
f(-5) = 23 
\]

The solution shows step-by-step how to substitute \( x = -5 \) into the function \( f(x) = x^2 - 2 \) and calculate the result, which is 23.

Note: There is also a part of another equation visible at the bottom starting with:

\[ 
c) \quad y = |3x - 1| 
\]

However, it is partially obscured, and no further information is available from the visible section.
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Transcribed Image Text:The image contains a portion of a math problem and its solution explaining a function evaluation. ### Function Evaluation #### Problem: Evaluate the function \( f(x) \) at \( x = -5 \). #### Solution: \[ c) \quad f(-5) = \] Calculating: \[ f(-5) = (-5)^2 - 2 \] \[ f(-5) = 25 - 2 \] \[ f(-5) = 23 \] The solution shows step-by-step how to substitute \( x = -5 \) into the function \( f(x) = x^2 - 2 \) and calculate the result, which is 23. Note: There is also a part of another equation visible at the bottom starting with: \[ c) \quad y = |3x - 1| \] However, it is partially obscured, and no further information is available from the visible section.
Expert Solution
Check Mark
Step 1

A relation is said to be a function only when every point in the domain has a unique value in the range.

 if f(x) is a function then for x is equal to any value there must be a unique f(x) . If any of the point in the domain will give more than one range then the relation will not be a function.

To check whether the given relation is a function or not we can use vertical line test. Draw the graph of the given relation, if a vertical line crosses the relation on the graph only once in all location then the relation is a function.

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