Is a all numbers x for which 4 2 #include "interval.h"
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- #include <stdio.h> #include <stdlib.h> #include <string.h> #define EMPS_SIZE 20 #define SSN_SIZE 9 #define MAX_EMPS 19 typedef struct { int salary; int yearBorn; char ssn[SSN_SIZE]; char * name; } Employee; Employee * emps[EMPS_SIZE]; int totalEmps = 0; void main(void) { int end = 1; char * command; char buff[256]; char * findEmp; char findBuff[256]; char * sortType; char sortBuff[256]; char hire[] = "HIRE"; char list[] = "LIST"; char quit[] = "QUIT"; char find[] = "FIND"; char fire[] = "FIRE"; char _sort[] = "SORT"; char salary[] = "SALARY"; char name[] = "NAME"; char save[] = "SAVE"; printf("Welcome to the Employee Manager dashboard!\n"); while (end) { printf("Would you like to HIRE, LIST, FIND, FIRE, SORT,SAVE or QUIT?\n\n"); scanf("%s", buff); command = malloc(strlen(buff + 1)); strcpy(command, buff); printf("You entered the command: %s\n\n", command);…5- int fun() int a, b, c, result; cout>a>>b>>c; cout<<"The result is "; reutrn result; } The error is Your answer#ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…
- What input or parameter value impacts the number of times the recursive function will be called. • Give three specific examples of input/parameter values and, for each, state the number of times the recursive function will be called. • Devise a formula with respect to n that describes the number of times the recursive function will be called, where n is either the value passed or some property of the value passed (e.g. n might be the length of a string of the size of an array).#include #include #include struct Point2d { double x; double y; void print() { // example: (2.5,3.64) std::cout << "(" << x << "," << y << ")" << std::endl; } double length() const { return std::sqrt(x * x + y * y); } // const Point2D & ==> function can't modify 'other' // the second const ==> function can't modify x, y Point2d add(const Point2d &other) const { Point2d result; result.x = x + other.x; result.y = y + other.y; return result; } }; // // do NOT modify above this line // Point2d discplacement(std::string commands) { // TODO: re-write this Point2d p = {0, 0}; return p; } // // do NOT modify below this line // void check(Point2d result, double x , double y) { if (result.x != x || result.y != y) { std::cout << "fail" << std::endl; } else { std::cout << "pass" << std::endl; } } int main() { Point2d result =…Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax
- in c language typedef _people { int age; char name[ 32 ] ; } People_T ; People_T data [ 3 ]; Using string lib function, Assign 30 and Cathy to the first cell, Assign 40 and John to the second cell and Assign 50 and Tom to the third cellEXPLAIN THIS CODE EACH LINE #include <stdio.h>#include<string.h>int main(){ char name[20]; int meal,quantity; int drink,quantity2; char choose_meal[30] = ""; int meal_price; float drink_price, orderPrice; char choose_drink[30] = ""; float cash, change; printf("--------------------Marry's Fast Food--------------------"); printf("\n"); printf("Enter your name: "); scanf("%s", name); printf("Hello %s!\n", name); printf("\n\nWhat would you like to order?\n"); printf("------------------------MEALS------------------------\n\n"); printf("[1] 1 pc. Chicken Joy....................Php 76.00\n"); printf("[2] 1 pc. w/Jolly spaghetti..............Php 99.00\n"); printf("[3] pc. Spaghetti........................Php 55.00\n"); printf("[4] pc. Burger steak w/rice..............Php 85.00\n"); printf("[5] pc. Burger...........................Php 30.00\n\n"); printf("Choose a number…You can dereference a smart pointer with the * operator. True FalseL et D= { s, d, b}, E= { c, k}, G= { a, k }, U={a, b, c, d, k, s} DUE=SEE MORE QUESTIONS