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![**Scenario:**
Ironman steps from the top of a tall building. He falls freely from rest to the ground a distance of \( h \). He falls a distance of \( \frac{h}{4} \) in the last interval of time of 1.1 s of his fall.
**Hint:**
First, compute the velocity when Ironman reaches the height equal to the distance fallen. This requires that you do the following: define the origin as the bottom of the building. Then use
\[ x - x0 = -v0 \times (t-t0) - (1/2)g(t-t0)^2 \]
where \( x = 0 \) and \( x0 = \text{(distance fallen)} \) and \( t - t0 \) is the time interval given. In this formulation, you are going to get the magnitude of \( v0 \) since you already inserted the sign.
You then insert \( v0 \) that you just calculated into the kinematic equation that involves \( v, g, \) and displacement \((v^2 - v0^2 = 2g(\text{height} - \text{(distance fallen)}))\), but now \( v \) (which is the final velocity is \( v0 \) from above) and \( v0 \) in this case is the velocity that Ironman has when he begins to fall, which is 0.
This gives a quadratic equation for height \( h \), and you will need to use the binomial equation to solve for \( h \). Choose the larger of the two solutions.
**Question:**
What is the height \( h \) of the building?
*Express your answer using two significant figures.*
**Input:**
\( h = 392.476 \, \text{m} \)
**Feedback:**
Incorrect; Try Again; 4 attempts remaining.](https://content.bartleby.com/qna-images/question/7ff1c888-964e-4444-aacc-2152d4151491/4be89740-c09f-4372-b417-4d5bef419eaa/lrq55i5_processed.png)
Transcribed Image Text:**Scenario:**
Ironman steps from the top of a tall building. He falls freely from rest to the ground a distance of \( h \). He falls a distance of \( \frac{h}{4} \) in the last interval of time of 1.1 s of his fall.
**Hint:**
First, compute the velocity when Ironman reaches the height equal to the distance fallen. This requires that you do the following: define the origin as the bottom of the building. Then use
\[ x - x0 = -v0 \times (t-t0) - (1/2)g(t-t0)^2 \]
where \( x = 0 \) and \( x0 = \text{(distance fallen)} \) and \( t - t0 \) is the time interval given. In this formulation, you are going to get the magnitude of \( v0 \) since you already inserted the sign.
You then insert \( v0 \) that you just calculated into the kinematic equation that involves \( v, g, \) and displacement \((v^2 - v0^2 = 2g(\text{height} - \text{(distance fallen)}))\), but now \( v \) (which is the final velocity is \( v0 \) from above) and \( v0 \) in this case is the velocity that Ironman has when he begins to fall, which is 0.
This gives a quadratic equation for height \( h \), and you will need to use the binomial equation to solve for \( h \). Choose the larger of the two solutions.
**Question:**
What is the height \( h \) of the building?
*Express your answer using two significant figures.*
**Input:**
\( h = 392.476 \, \text{m} \)
**Feedback:**
Incorrect; Try Again; 4 attempts remaining.
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