What is the IR and HNMRAndCNMR and mass in this example IR Spectrum(liquid film)4000300059100806040204013C NMR Spectrum(100 MHz CDCI, solution)% of base peak8780DEPT CH CH. CHproton decoupled200¹H NMR Spectrum(400 MHz, CDCI, solution)109817391600v (cm¹)2000115M 146-1%120 160m/emm1200800Mass SpectrumC6H10042801607200 24012065solvent804Problem 44No significant UVabsorption above 220 nm0403218 (ppm)TMS08 (ppm)13

Answered: Image /qna-images/answer/3fbbf0b2-ef40-4de6-94dc-1bcee0b3dfb4.jpg

IR Spectrum (liquid film) 4000 100 80 % of base peak 3000 60 40 20 40 13C NMR Spectrum (100 MHz CDCI, solution) 59 80 DEPT CH CH. CH proton decoupled www. 200 ¹H NMR Spectrum (400 MHz, CDCI, solution) 1739 2000 v (cm') 115 120 1600 M 145-1% 160 m/e 160 MY 800 Mass Spectrum C6H1004 280 solvent 80 1200 200 240 120 Problem 44 No significant UV absorption above 220 nm 0 40 8 (ppm)

IR Spectrum (liquid film) 4000 100 80 % of base peak 3000 60 40 20 40 13C NMR Spectrum (100 MHz CDCI, solution) 59 80 DEPT CH CH. CH proton decoupled www. 200 ¹H NMR Spectrum (400 MHz, CDCI, solution) 1739 2000 v (cm') 115 120 1600 M 145-1% 160 m/e 160 MY 800 Mass Spectrum C6H1004 280 solvent 80 1200 200 240 120 Problem 44 No significant UV absorption above 220 nm 0 40 8 (ppm)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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