interval dt.In order to do that we spend dW(t) amount of energy. BydefinitiondW(1)=V(1)dq(t),In short hand notationdW-VdqSince the capacitance of capacitor is C=Q/V, when the total charge at pointa is Q show that the total energy of capacitor isU-Q?2Cd) For a spherical capacitor and b=x case, show that.U=-8TE ae) Calculate U by using the given quantities: a=10 cm, Q=2x10 C. Question 2Suppose that there is a spherical capacitor with inner radius a and outer radiusb.a) Find the capacitance of this conductor in terms of a and b.b) When the outer radius b goes to infinity, show thatC= 4 nE, a,c) While you are cheging the capacitor, infinitesimal small charges is movedfrom one plate to other one under potential difference V(t) at any time. Thetcharge is called as dq(t), and we move this charge from a to b in time

To determine: Capacitance of this capacitor. C=4πε0a Total energy of capacitor is U=Q22C U=Q28πε0a…

interval dt.In order to do that we spend dW(t) amount of energy. By definition dW(t)=V(t)dq(t), In short hand notation dW=Vdq. Since the capacitance of capacitor is C=Q/V. when the total charge at point a is Q show that the total energy of capacitor is U- Q? 20 d) For a spherical capacitor and b=x case. show that. U= Q? STE a e) Calculate U by using the given quantities: a=10 cm O

interval dt.In order to do that we spend dW(t) amount of energy. By definition dW(t)=V(t)dq(t), In short hand notation dW=Vdq. Since the capacitance of capacitor is C=Q/V. when the total charge at point a is Q show that the total energy of capacitor is U- Q? 20 d) For a spherical capacitor and b=x case. show that. U= Q? STE a e) Calculate U by using the given quantities: a=10 cm O

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter26: Capacitance And Dielectrics

Section: Chapter Questions

Problem 26.14P: What If? The two capacitors of Problem 13 (C1 = 5.00 F and C2 = 12.0 F) are now connected in series...

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