Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X6- x₂ = X3 = X4= 30➤ X5 = X is free 100 x₁ is free x2 = X3 is free X4 is free 120 130 CIND xs X5 = x6 is free X₁ What the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice. O A. O B. O C. X, is free E 1x6 F 40 100 x₁ = x2 = x3 = X4 = X5 = xe is free X6 O D. X₁ X₂ is free x3 = X5 is free X is free

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter4: Equations Of Linear Functions
Section4.3: Parallel And Perpendicular Lines
Problem 33PPS
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Intersections in England are often constructed as one-way
"roundabouts," such as the one shown in the figure. Assume that
traffic must travel in the directions shown. Find the general
solution of the network flow. Find the smallest possible value for
X6.
30 >
×2=
X3
X4
X5
X6 is free
100
X₁ is free
X2=
X3 is free
X₁ is free
B,
X5 =
X6 is free
X₂A
120 130
X3
X4
X1
D
X5
E
Yx6
/F
X6
What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice.
O A.
O B.
O C.
x₁ is free
40
100
-C
‒‒‒‒‒
X₁ =
x₂ =
X3 =
X4=
X5 =
X6 is free
O D.
X₁ =
X₂ is free
x3 =
X4
=
X5 is free
X6 is free
Transcribed Image Text:Intersections in England are often constructed as one-way "roundabouts," such as the one shown in the figure. Assume that traffic must travel in the directions shown. Find the general solution of the network flow. Find the smallest possible value for X6. 30 > ×2= X3 X4 X5 X6 is free 100 X₁ is free X2= X3 is free X₁ is free B, X5 = X6 is free X₂A 120 130 X3 X4 X1 D X5 E Yx6 /F X6 What is the general solution of the network flow? Choose the correct answer below and fill in the answer boxes to complete your choice. O A. O B. O C. x₁ is free 40 100 -C ‒‒‒‒‒ X₁ = x₂ = X3 = X4= X5 = X6 is free O D. X₁ = X₂ is free x3 = X4 = X5 is free X6 is free
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