int a[10] = {0,1,2,3,4,5,6,7,8,9}; int *m = &a[0]; int *p = &a[5]; int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *p

#include <stdio.h>   int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key);   int *joinArray(int arrA[], int arrB[]) {     int j = 0;     if ((arrB[0] + arrB[4]) % 5 == 0)     {         arrB[0] = 0;         arrB[4] = 0;     }       for (int i = 0; i < 5; i++)     {         arrC[j++] = arrA[i];           if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1))         {             continue;         }         else             arrC[j++] = arrB[i];     }       for (int i = 0; i < j; i++)     {         int temp;         for (int k = i + 1; k < j; k++)         {             if (arrC[i] > arrC[k])             {                 temp = arrC[i];                 arrC[i] = arrC[k];                 arrC[k] = temp;             }         }     }     for (int i = 0; i < j; i++)     {         printf("%d ", arrC[i]);     }     return arrC; }   int bSearch(int arr[], int l, int h, int key) {     if (h >= l)     {         int mid = l + (h - l) / 2;           if…

# dates and times with lubridateinstall.packages("nycflights13") library(tidyverse)library(lubridate)library(nycflights13) Qustion: Create a function called date_quarter that accepts any vector of dates as its input and then returns the corresponding quarter for each date Examples: “2019-01-01” should return “Q1” “2011-05-23” should return “Q2” “1978-09-30” should return “Q3” Etc. Use the flight's data set from the nycflights13 package to test your function by creating a new column called quarter using mutate()

int main(int argc, char **argv) { float *rainfall; float rain_today; // rainfall has been dynamically allocated space for a floating point number. // Both rainfall and rain today have been initialized in hidden code. // Assign the amount in rain_today to the space rainfall points to. return 0; }

Given the following declaration : char msg[100] = "Department of Computer Science";     What is printed by: strcpy_s(msg, "University"); int len = strlen(msg); for (int i = len-3; i >0; i--) {       msg[i] = 'x';     }       cout << msg;