Instructions: 1. In the code editor, you are provided a main() function that asks the user for a word. This word is then passed to a function called, hasvowel(). 2. Your task is to define the hasVowel) function which has the following details 1. Return type - int 2. Name - hasvowel 3. Parameter: 1. char - to hold the character array 4. Return value - 1 if there is at least 1 vowel and 0 if there is none. Be sure to consider both the capital and small letter vowels when checking. Input 1. The word Output Enter the word: CodeChun There is a vowel in the word- "CodeChun"
Instructions: 1. In the code editor, you are provided a main() function that asks the user for a word. This word is then passed to a function called, hasvowel(). 2. Your task is to define the hasVowel) function which has the following details 1. Return type - int 2. Name - hasvowel 3. Parameter: 1. char - to hold the character array 4. Return value - 1 if there is at least 1 vowel and 0 if there is none. Be sure to consider both the capital and small letter vowels when checking. Input 1. The word Output Enter the word: CodeChun There is a vowel in the word- "CodeChun"
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
help me with the expected output on the photo
source code:
#include<stdio.h>
int main(void) {
char word[100];
printf("Enter the word: ");
scanf("%s", word);
int result = hasVowel(word);
if(result == 1) {
printf("There is a vowel in the word \"%s\"", word);
} else if(result == 0) {
printf("There is no vowel in the word \"%s\"", word);
}
return 0;
}
![main.c
3. The proposal!
1
#include<stdio.h>
by CodeChum Admin
2
Thanks to your help again, I found the perfect ring for her. I'm going to propose
3 int nain(void) 1
4
char word [100];
5
tomorrow but I'm nervous. I think when I'm going to ask her the famous
printf("Enter the word: ");
scanf("ks", word);
question, "Will you marry me?", she's going to respond with:
"Only if you can determine if there is a vowel in a certain word"
int result = hasVowel(word);
10
if(result = 1) {
printf("The re is a vowel in the word "%s\"", word);
} else if(result == 0) {
printf("The re is no vowel in the word "%s\"", word);
11 -
Shucks! It's always better to be prepared. Who knows that might indeed happen.
12
I'm going to need your help to create function that'll do this so tomorrow, I will
13-
just call this function.
14
15
16
17
return 0;
Instructions:
18
1. In the code editor, you are provided a main() function that asks the user
for a word. This word is then passed to a function called, hasVowel().
2. Your task is to define the hasVowel() function which has the following
details
1. Return type - int
2. Name - hasvowel
3. Parameter:
1. char* - to hold the character array
4. Return value - 1 if there is at least 1 vowel and O if there is none. Be
sure to consider both the capital and small letter vowels when
checking.
Input
1. The word
Output
Enter the word: CodeChun
There is a vowel in the word "CodeChun"](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb3210701-74b9-4350-a073-c4781ff9425b%2F1f3b81f8-ed32-44a8-95c5-99dacc6bf85a%2Fn6czcy_processed.png&w=3840&q=75)
Transcribed Image Text:main.c
3. The proposal!
1
#include<stdio.h>
by CodeChum Admin
2
Thanks to your help again, I found the perfect ring for her. I'm going to propose
3 int nain(void) 1
4
char word [100];
5
tomorrow but I'm nervous. I think when I'm going to ask her the famous
printf("Enter the word: ");
scanf("ks", word);
question, "Will you marry me?", she's going to respond with:
"Only if you can determine if there is a vowel in a certain word"
int result = hasVowel(word);
10
if(result = 1) {
printf("The re is a vowel in the word "%s\"", word);
} else if(result == 0) {
printf("The re is no vowel in the word "%s\"", word);
11 -
Shucks! It's always better to be prepared. Who knows that might indeed happen.
12
I'm going to need your help to create function that'll do this so tomorrow, I will
13-
just call this function.
14
15
16
17
return 0;
Instructions:
18
1. In the code editor, you are provided a main() function that asks the user
for a word. This word is then passed to a function called, hasVowel().
2. Your task is to define the hasVowel() function which has the following
details
1. Return type - int
2. Name - hasvowel
3. Parameter:
1. char* - to hold the character array
4. Return value - 1 if there is at least 1 vowel and O if there is none. Be
sure to consider both the capital and small letter vowels when
checking.
Input
1. The word
Output
Enter the word: CodeChun
There is a vowel in the word "CodeChun"
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