Inspect the code and in your own interpretation, describe the reason call to function ChangeIt_1(n) will not change x in main()?
Inspect the code and in your own interpretation, describe the reason call to function ChangeIt_1(n) will not change x in main()?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
- Inspect the code and in your own interpretation, describe the reason call to function ChangeIt_1(n) will not change x in main()?
- Inspect the code and in your own interpretation, describe the reason parameter n in ChangeIt_2(int *n) is a pointer, and statement in the function is *n = 6 ?
- Write a function called void swap with two parameters, which will receive the address of x and y as pointer. The function should swap the value of x and y only if x is larger than y. Print the value of x and y after the function call.
- Write a function called double getAverage(int *array, int SIZE), where it accept the array as pointer, and return the average of the array. Print the returned value from this function. Always use *array rather than subscript to access the array value.
![#include <iostream>
using namespace std;
3
49 void ChangeIt_1(int n) {
n = 5;
}
5
7
8E void ChangeIt_2(int *n) {
*n = 6;
10
}
11
12 E void ChangeIt_3(int &n) {
13
n = 73
14
}
15
int ChangeIt_4(int n) {
n = 8;
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17
18
return n;
19
}
20
21 E main(){
int *p;
//declare p as pointer
int x=10, y=7, SIZE=5, data[SIZE]={1,3,2,5,4};
//reference of x
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24
p=8x;
25
ChangeIt_1(x);
cout « "ChangeIt_1
26
27
« *p « endl;
28
ChangeIt_2(8x);
cout <« "ChangeIt_2
29
: " « *p « endl;
30
31
32
ChangeIt_3(x);
cout « "ChangeIt_3
« *p « endl;
33
34
ChangeIt_4(x);
cout <« "ChangeIt_4
}
35
X =
36
« *p « endl;
37
38
N 22 22](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33205080-cf09-47ad-a4d7-f5a8f95998ad%2Fa19d682b-0ec1-4757-96e3-f97bedbab676%2Fmxyc3il_processed.png&w=3840&q=75)
Transcribed Image Text:#include <iostream>
using namespace std;
3
49 void ChangeIt_1(int n) {
n = 5;
}
5
7
8E void ChangeIt_2(int *n) {
*n = 6;
10
}
11
12 E void ChangeIt_3(int &n) {
13
n = 73
14
}
15
int ChangeIt_4(int n) {
n = 8;
16
17
18
return n;
19
}
20
21 E main(){
int *p;
//declare p as pointer
int x=10, y=7, SIZE=5, data[SIZE]={1,3,2,5,4};
//reference of x
23
24
p=8x;
25
ChangeIt_1(x);
cout « "ChangeIt_1
26
27
« *p « endl;
28
ChangeIt_2(8x);
cout <« "ChangeIt_2
29
: " « *p « endl;
30
31
32
ChangeIt_3(x);
cout « "ChangeIt_3
« *p « endl;
33
34
ChangeIt_4(x);
cout <« "ChangeIt_4
}
35
X =
36
« *p « endl;
37
38
N 22 22
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