Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of 305 N/C.   (a) What is the magnitude of the acceleration of the electron (in m/s2)?     (b) The electron is initially at rest. What is its speed (in m/s) after 1.05 ✕ 10−8 s?

An electron is traveling through a uniform electric field. The field is constant and given by E=(2.00×10−11N/C) i^− (1.20×10−11N/C) j^. At t=0 , the electron is at the origin and traveling in the x direction with a speed of 2.20 m/s. Part A) What is its position 2.50 s later? x= ?   (in m)  Part B) y=?

An electron is moving horizontally at 3 x 10^6 m/s when it enters an electric field. If the electron deflects 0.9 cm downward in a distance of 2.5 cm determine the magnitude and direction of the electric field.

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle with the same mass as an electron but the opposite charge (+e). If a positron is accelerated by a constant electric field of magnitude 271 N/C, find the following. (a) Find the acceleration of the positron. m/s² (b) Find the positron's speed after 6.50 x 10-9 s. Assume that the positron started from rest. m/s