A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN: 9780134753119
Author: Sheldon Ross
Publisher: PEARSON
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Inside a bag there are 3 green balls, 2 red balls and 2 yellow balls. Two balls are randomly drawn without replacement. Calculate the probability of drawing one green ball and one yellow ball. The tree diagram has been started.

 

This image shows a tree diagram used to represent probabilities related to a specific event, involving colors labeled G, R, and Y.

### Description:

1. **Initial Branches:**
   - The diagram begins with a single point branching into three lines representing three different outcomes in the first event.
     - The branch labeled "G" has a probability of \( \frac{3}{7} \).
     - The branch labeled "R" has a probability of \( \frac{2}{7} \).
     - The branch labeled "Y" has a probability of \( \frac{2}{7} \).

2. **Secondary Branches (Starting from G):**
   - The "G" branch further splits into three outcomes:
     - Another "G" with a probability of \( \frac{2}{6} \).
     - An "R" with a probability of \( \frac{2}{6} \).
     - A "Y" with a probability of \( \frac{2}{6} \).

This tree diagram effectively lays out the pathway and corresponding probabilities for a sequence of events concerning the selection of colors. It is a visual method to help in calculating the probabilities of combined events.
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Transcribed Image Text:This image shows a tree diagram used to represent probabilities related to a specific event, involving colors labeled G, R, and Y. ### Description: 1. **Initial Branches:** - The diagram begins with a single point branching into three lines representing three different outcomes in the first event. - The branch labeled "G" has a probability of \( \frac{3}{7} \). - The branch labeled "R" has a probability of \( \frac{2}{7} \). - The branch labeled "Y" has a probability of \( \frac{2}{7} \). 2. **Secondary Branches (Starting from G):** - The "G" branch further splits into three outcomes: - Another "G" with a probability of \( \frac{2}{6} \). - An "R" with a probability of \( \frac{2}{6} \). - A "Y" with a probability of \( \frac{2}{6} \). This tree diagram effectively lays out the pathway and corresponding probabilities for a sequence of events concerning the selection of colors. It is a visual method to help in calculating the probabilities of combined events.
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