Initial (M) Change (M) Equilibrium (M) -2.0 Consider the equilibrium system described by the chemical reaction below. A mixture of gas containing only N₂ and H₂ is reacted in a vessel at high temperature. At equilibrium, the 5.0 M H₂, 8.0 M N2, and 4.0 M NH3 are present. Determine the initial concentrations of H₂ and N₂ that were present in the vessel. Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. 0 2.0 5.0 N₂(g) + 3 H₂(g) = 2 NH3(g) -5.0 N₂(g) 8.0 1 6.0 4.0 -6.0 3 H₂(g) -4.0 10.0 2 NH,(9) RESET 11.0

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Initial (M)
Change (M)
Equilibrium (M)
-2.0
Consider the equilibrium system described by the chemical reaction
below. A mixture of gas containing only N₂ and H₂ is reacted in a vessel at
high temperature. At equilibrium, the 5.0 M H2, 8.0 M N₂, and 4.0 M NH3
are present. Determine the initial concentrations of H₂ and N₂ that were
present in the vessel.
Based on the given values, fill in the ICE table to determine concentrations of all
reactants and products.
0
2.0
5.0
N₂(g) + 3 H₂(g) = 2 NH3(g)
-5.0
N₂(g)
Ssivestit
8.0
1
6.0
+
4.0
-6.0
3 H₂(g)
ઇસ્કો અને કોની
-4.0
10
10.0
2 NH3(g)
RESET
11.0
Transcribed Image Text:Initial (M) Change (M) Equilibrium (M) -2.0 Consider the equilibrium system described by the chemical reaction below. A mixture of gas containing only N₂ and H₂ is reacted in a vessel at high temperature. At equilibrium, the 5.0 M H2, 8.0 M N₂, and 4.0 M NH3 are present. Determine the initial concentrations of H₂ and N₂ that were present in the vessel. Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. 0 2.0 5.0 N₂(g) + 3 H₂(g) = 2 NH3(g) -5.0 N₂(g) Ssivestit 8.0 1 6.0 + 4.0 -6.0 3 H₂(g) ઇસ્કો અને કોની -4.0 10 10.0 2 NH3(g) RESET 11.0
Expert Solution
Step 1

Given data is

Molarity of N2 at equilibrium= 8 M

Molarity of H2 at equilibrium= 5 M 

Molarity of NH3 at equilibrium = 4M 

N2(g) + 3H2(g) <===> 2NH3(g)

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