∞ k=1 (-1)+¹(x - 1)k k

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Determine the radius and interval of convergence of the following power series.

Also make sure to check the intervals to see if they converge or diverge.

Show every step.

The image contains a mathematical expression representing an infinite series. The series is written as:

\[
\sum_{k=1}^{\infty} \frac{(-1)^{k+1}(x-1)^k}{k}
\]

Explanation:

- The symbol \(\sum_{k=1}^{\infty}\) indicates that this is a summation, or series, starting from \(k = 1\) and continuing to infinity.
- \((-1)^{k+1}\) introduces an alternating sign to each term in the series.
- \((x-1)^k\) represents the variable component of the series, raised to the power of \(k\).
- The entire expression is divided by \(k\), which is the index of summation.

This is typically related to alternating series and can be found in contexts such as the expansion of logarithmic functions.
Transcribed Image Text:The image contains a mathematical expression representing an infinite series. The series is written as: \[ \sum_{k=1}^{\infty} \frac{(-1)^{k+1}(x-1)^k}{k} \] Explanation: - The symbol \(\sum_{k=1}^{\infty}\) indicates that this is a summation, or series, starting from \(k = 1\) and continuing to infinity. - \((-1)^{k+1}\) introduces an alternating sign to each term in the series. - \((x-1)^k\) represents the variable component of the series, raised to the power of \(k\). - The entire expression is divided by \(k\), which is the index of summation. This is typically related to alternating series and can be found in contexts such as the expansion of logarithmic functions.
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