ind the z value that corresponds to the given area in the figure below 0.4505. Use The Standard Normal Distribution Table and enter the answer to 2 decimal places.

Find the Z-scores that separate the middle 56% of the distribution from the area in the tails of the standard normal distribution. Click the icon to view a table of areas under the normal curve. The Z-scores are (Use a comma to separate answers as needed. Round to two decimal places as needed.)

Use the standard normal table to find the z-score that corresponds to the cumulative area 0.0129. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. Click to view page 2 of the standard normal table. (Type an integer or decipaall eaundad to thcee deeisel elese apeaded - X Standard normal table (page 2) Standard normal table (page 1) Standard Normal Distribution Standard Normal Distribution Critical Values Critical Values Level of Confidence c Level of Confidence c 0.80 1.28 0.80 1.28 0.90 1.645 Area 0.90 1.645 0.95 1.96 0.95 1.96 0.99 2.575 0.99 2.575 .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 .09 .08 .07 .06 05 .04 .03 .02 .01 .00 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 - 3.4 - 3.3 - 3.2 - 3.1 - 3.0 - 2.9 .0002 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 0.1 .5398 .5438 .5478 .5517…

Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1.   The area of the shaded region is   ​(Round to four decimal places as​ needed.)

Find the z-score that has 70.5% of the distribution's area to its right. The z-score is (Round to two decimal places as needed.)

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Find the area of the shaded region. The graph depicts the standard normal distribution with mean O and standard deviation 1. Click to view page 1 of the table. Click to view page 2 of the table. The area of the shaded region is (Round to four decimal places as needed.) z = 0.83