Practice Problem 6.Find the voltage across each of the capacitors in Fig. 6.20.40 μF60 µFAnswer: U=45 V, U2 = 45 V, v3 = 15 V, v4 30 V.+ 1 -+ v3 -90 V20 μF30V4Figure 6.20For Practice Prob. 6.7.

The circuit can be made as: The equivalent capacitance of the circuit can be found out: The 30 and…

Answered: ind the voltage across each of the…

ind the voltage across each of the capacitors in Fig. 6.20. 40 µF 60 µF nswer: U = 45 V, v2 = 45 V, U3 = 15 V, v4 = 30 V. %3D %3D + v3 - 90 V #2 수 20μF Figure 6.20 For Practice Prob. 6.7. +

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter19: Capacitors

Section: Chapter Questions

Problem 2PA: You are an electrician working in an industrial plant. You discover that the problem with a certain...

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Concept explainers

Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.

Question

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Practice Problem 6.
Find the voltage across each of the capacitors in Fig. 6.20.
40 μF
60 µF
Answer: U=
45 V, U2 = 45 V, v3 = 15 V, v4 30 V.
+ 1 -
+ v3 -
90 V
20 μF
30
V4
Figure 6.20
For Practice Prob. 6.7.

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