ind the point of intersection for the lines v(t) = (-5, - 8, -6)t + (− 1, 3, 1) and (u) = (6, 6, 2)u + (16, 23, 11). || || ||

(c) √ z²dx-zdy+2ydz; C: the line segments from (0,0,0) to (0,1,1), from (0,1,1) to 77 (1,2,3), and from (1,2,3) to (1,2,4). (ans: 6

Find the distance from the point (4,-4,-5) to the line a(t) = (3, 1, — 4)t + (9, — 5,3)

Which lines are parallel? 1:7(1) = (7+2 · 7) + t · (7 – 2 ·7 +3.7), 1,: ,(u) = (7 + 2 - R ) + u · ( 7 + 2 ·} – 3. R), 13: r(v) = (6-7-7) – v· (2.7 – 4:7 +6.F), - V. 4:7(w) = .7- w:7 - (1 • W 2 • W 3 OUniversit

Find the distance from the point (-3,0,-7) to the line a(t)=<-3,0,-4>t + <0,7,-4>

Let v (a) 20 = - (1, 4, 2) and w 4w = (b) Let s = t = = (1, - 4,0). (-2,24,4) (t, 1, 0). For which value(s) of t are w and 3 parallel?