ind the crea bclOW the Stand erd normal curvc to tne Cgnt of z= 0.2

The figure represents the normal curve with u= 266 days and o=16 days. The area to the right of x = 280 is 0.1908 . Provide two interpretations of this area

Suppose the lengths of human pregnancies are normally distributed with μ = 266 days and o= 16 days. Complete parts (a) and (b) below. (a) The figure to the right represents the normal curve with μ = 266 days and o= 16 days. The area to the left of X = 230 is 0.0122. Provide two interpretations of this area. Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) A. The proportion of human pregnancies that last less than 230 days is 0.0122. OB. The proportion of human pregnancies that last more than days is Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The probability that a randomly selected human pregnancy lasts less than OB. The probability that a randomly selected human pregnancy lasts more than days is days is ^. X 230 266

Find a z-score such that 56% of the area under the standard normal curve is below that score. Z= Click the icon to view the area under the standard normal curve table. (Round to the nearest hundredth as needed.)

Find the area under the standard normal curve between these values: ?=0 ??? ?=1.3

Z is distributed as a standard normal variable. Use Excel to find Pr(Z > -2.43).

Find the area under the standard normal curve between z= 1.5 and z= 2.5. %3D O A. 0.9816 О В. 0.9938 С. 0.0606 O D. 0.9332

find the area under the standard normal curve to the left of z=1.5

Calculate the area under the Standard Normal Curve to the left of the value of z = 8.55.

fine the area under the normal standard curve that lies between z=1.26 and z=2.32