Include a CLAIM: answer the question. For example, this answer is not correct. Include EVIDENCE: Describe what you see in the calculation work that supports your claim. Include REASONING: Explain WHY you selected that evidence to support your claim.   YOUR answer to this question should be an explanation CER. Provide

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Include a CLAIM: answer the question. For example, this answer is not correct.

Include EVIDENCE: Describe what you see in the calculation work that supports your claim.

Include REASONING: Explain WHY you selected that evidence to support your claim.

 

YOUR answer to this question should be an explanation CER. Provide additional details and use subject specific language. Cite evidence from the calculation. Connect the evidence to the claim.


You can use this to start off your answer:

No, this answer is not correct. In the calculation, the wrong conversion factor is used. The conversion used in the answer is 1 mole/ 102.2 grams instead of 102.2 grams/1 mole. When we solve dimensional analysis the units must cancel out....

In class, students were given the following problem:
"Aluminum satellite dishes resist corrosion because aluminum reacts with oxygen gas (0₂) to form a
coating of aluminum oxide (Al2O3) according to the following chemical equation:
4Al(s) + 302(g) →2A/203(s)
What is the mass of 9.45 moles of Al 203?
After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion:
1 mole AL, Q
9.45 moles Al₂O3× 102.2 grams of Al, 0,
Is this answer correct?
= 0.0926 grams of Al2O3
Transcribed Image Text:In class, students were given the following problem: "Aluminum satellite dishes resist corrosion because aluminum reacts with oxygen gas (0₂) to form a coating of aluminum oxide (Al2O3) according to the following chemical equation: 4Al(s) + 302(g) →2A/203(s) What is the mass of 9.45 moles of Al 203? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole AL, Q 9.45 moles Al₂O3× 102.2 grams of Al, 0, Is this answer correct? = 0.0926 grams of Al2O3
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