Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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### Differential Equations: Solving Second-Order Initial Value Problems (IVPs)

#### Problem Statement:
Consider the second-order differential equation given by:

\[ x'' + x = 0. \]

A general solution to this differential equation is

\[ x(t) = c_1 \cos t + c_2 \sin t, \]

where \( c_1 \) and \( c_2 \) are constants. This general solution is a two-parameter family of solutions.

#### Given Initial Conditions:
- \( x(0) = -1 \)
- \( x'(0) = 7 \)

#### Task:
Find a particular solution of the differential equation that satisfies the given initial conditions.

#### Solution:
To solve this IVP, we need to determine the values of \( c_1 \) and \( c_2 \) that fit the initial conditions provided.

1. **Initial Condition:** \( x(0) = -1 \)

    Substitute \( t = 0 \) into the general solution:
    \[
    x(0) = c_1 \cos(0) + c_2 \sin(0) = c_1 \cdot 1 + c_2 \cdot 0 = c_1
    \]
    
    Thus, we have \( c_1 = -1 \).

2. **Initial Condition:** \( x'(0) = 7 \)

    First, find the derivative of the general solution:
    \[
    x'(t) = -c_1 \sin t + c_2 \cos t
    \]

    Now, substitute \( t = 0 \):
    \[
    x'(0) = -c_1 \sin(0) + c_2 \cos(0) = -c_1 \cdot 0 + c_2 \cdot 1 = c_2
    \]

    Thus, we have \( c_2 = 7 \).

Therefore, the particular solution that satisfies the initial conditions is:

\[ x(t) = -\cos t + 7 \sin t \]

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Transcribed Image Text:### Differential Equations: Solving Second-Order Initial Value Problems (IVPs) #### Problem Statement: Consider the second-order differential equation given by: \[ x'' + x = 0. \] A general solution to this differential equation is \[ x(t) = c_1 \cos t + c_2 \sin t, \] where \( c_1 \) and \( c_2 \) are constants. This general solution is a two-parameter family of solutions. #### Given Initial Conditions: - \( x(0) = -1 \) - \( x'(0) = 7 \) #### Task: Find a particular solution of the differential equation that satisfies the given initial conditions. #### Solution: To solve this IVP, we need to determine the values of \( c_1 \) and \( c_2 \) that fit the initial conditions provided. 1. **Initial Condition:** \( x(0) = -1 \) Substitute \( t = 0 \) into the general solution: \[ x(0) = c_1 \cos(0) + c_2 \sin(0) = c_1 \cdot 1 + c_2 \cdot 0 = c_1 \] Thus, we have \( c_1 = -1 \). 2. **Initial Condition:** \( x'(0) = 7 \) First, find the derivative of the general solution: \[ x'(t) = -c_1 \sin t + c_2 \cos t \] Now, substitute \( t = 0 \): \[ x'(0) = -c_1 \sin(0) + c_2 \cos(0) = -c_1 \cdot 0 + c_2 \cdot 1 = c_2 \] Thus, we have \( c_2 = 7 \). Therefore, the particular solution that satisfies the initial conditions is: \[ x(t) = -\cos t + 7 \sin t \] #### User Interaction: The website provides an input field for users to type in their answer and a button labeled "Read It" for additional help and explanations. **Input Field:** - \( x = \) [ ] **Help Section (Button):** - **Need Help?** [Read
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