
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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Transcribed Image Text:In this problem, we walk through a general procedure of finding horizontal and vertical asymptotes of a function. Fill in the blanks and make the appropriate
selections to fill in the details of the following sketch.
Let f(x) =
-4z²-15z+4
(x+4)(x-4)
horizontal line with equation
Let's first find all horizontal asymptotes. First, we compute that_lim_ f(z) = Number
I→∞
is a horizontal asymptote.
Next, we evaluate lim f(x), and find that:
I→→∞0
lim f(z) exists and is not equal to
I→→∞
lim f(x) exists and is equal to
I→→∞0
∞--I
lim f(z). Thus, we have found a second horizontal asymptote.
I→∞
lim f(z). Thus, there isn't a second horizontal asymptote.
I→∞
lim f(z) does not exist. Thus, there isn't a second horizontal asymptote.
Now, we try to find the vertical asymptotes, which can only occur where f(z) is discontinuous. Notice that the function has two discontinuities, at x = -4
and at z = 4. Analyzing f(z) around + = -4, we find that
At least one of lim f(z), lim f(z) is infinite. Thus, z = -4 is indeed a vertical asymptote.
I→→4
2+-4+
Neither lim f(z) nor lim f(z) is infinite. Thus, z = -4 is not a vertical asymptote.
z+-4+
I→-4-
Finally, we analyze f(x) around = 4. We find that
At least one of lim_ f(z), lim f(z) is infinite. Thus, z = 4 is indeed a vertical asymptote.
I-4
2+4+
This tells us that the
Neither lim f(z) nor lim f(z) is infinite. Thus, z = 4 is not a vertical asymptote.
I-4
2+4+
Expert Solution

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Step 1: Define the problem
The given function is
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