Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
Bartleby Related Questions Icon

Related questions

Question
In this problem, we walk through a general procedure of finding horizontal and vertical asymptotes of a function. Fill in the blanks and make the appropriate
selections to fill in the details of the following sketch.
Let f(x) =
-4z²-15z+4
(x+4)(x-4)
horizontal line with equation
Let's first find all horizontal asymptotes. First, we compute that_lim_ f(z) = Number
I→∞
is a horizontal asymptote.
Next, we evaluate lim f(x), and find that:
I→→∞0
lim f(z) exists and is not equal to
I→→∞
lim f(x) exists and is equal to
I→→∞0
∞--I
lim f(z). Thus, we have found a second horizontal asymptote.
I→∞
lim f(z). Thus, there isn't a second horizontal asymptote.
I→∞
lim f(z) does not exist. Thus, there isn't a second horizontal asymptote.
Now, we try to find the vertical asymptotes, which can only occur where f(z) is discontinuous. Notice that the function has two discontinuities, at x = -4
and at z = 4. Analyzing f(z) around + = -4, we find that
At least one of lim f(z), lim f(z) is infinite. Thus, z = -4 is indeed a vertical asymptote.
I→→4
2+-4+
Neither lim f(z) nor lim f(z) is infinite. Thus, z = -4 is not a vertical asymptote.
z+-4+
I→-4-
Finally, we analyze f(x) around = 4. We find that
At least one of lim_ f(z), lim f(z) is infinite. Thus, z = 4 is indeed a vertical asymptote.
I-4
2+4+
This tells us that the
Neither lim f(z) nor lim f(z) is infinite. Thus, z = 4 is not a vertical asymptote.
I-4
2+4+
expand button
Transcribed Image Text:In this problem, we walk through a general procedure of finding horizontal and vertical asymptotes of a function. Fill in the blanks and make the appropriate selections to fill in the details of the following sketch. Let f(x) = -4z²-15z+4 (x+4)(x-4) horizontal line with equation Let's first find all horizontal asymptotes. First, we compute that_lim_ f(z) = Number I→∞ is a horizontal asymptote. Next, we evaluate lim f(x), and find that: I→→∞0 lim f(z) exists and is not equal to I→→∞ lim f(x) exists and is equal to I→→∞0 ∞--I lim f(z). Thus, we have found a second horizontal asymptote. I→∞ lim f(z). Thus, there isn't a second horizontal asymptote. I→∞ lim f(z) does not exist. Thus, there isn't a second horizontal asymptote. Now, we try to find the vertical asymptotes, which can only occur where f(z) is discontinuous. Notice that the function has two discontinuities, at x = -4 and at z = 4. Analyzing f(z) around + = -4, we find that At least one of lim f(z), lim f(z) is infinite. Thus, z = -4 is indeed a vertical asymptote. I→→4 2+-4+ Neither lim f(z) nor lim f(z) is infinite. Thus, z = -4 is not a vertical asymptote. z+-4+ I→-4- Finally, we analyze f(x) around = 4. We find that At least one of lim_ f(z), lim f(z) is infinite. Thus, z = 4 is indeed a vertical asymptote. I-4 2+4+ This tells us that the Neither lim f(z) nor lim f(z) is infinite. Thus, z = 4 is not a vertical asymptote. I-4 2+4+
Expert Solution
Check Mark
Step 1: Define the problem

The given function is f open parentheses x close parentheses equals fraction numerator negative 4 x squared minus 15 x plus 4 over denominator open parentheses x plus 4 close parentheses open parentheses x minus 4 close parentheses end fraction

Knowledge Booster
Background pattern image
Recommended textbooks for you
Text book image
Calculus: Early Transcendentals
Calculus
ISBN:9781285741550
Author:James Stewart
Publisher:Cengage Learning
Text book image
Thomas' Calculus (14th Edition)
Calculus
ISBN:9780134438986
Author:Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:PEARSON
Text book image
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:9780134763644
Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:PEARSON
Text book image
Calculus: Early Transcendentals
Calculus
ISBN:9781319050740
Author:Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:W. H. Freeman
Text book image
Precalculus
Calculus
ISBN:9780135189405
Author:Michael Sullivan
Publisher:PEARSON
Text book image
Calculus: Early Transcendental Functions
Calculus
ISBN:9781337552516
Author:Ron Larson, Bruce H. Edwards
Publisher:Cengage Learning