In this problem, the friction is equal to zero. Vector A along the positive X axis = 14.0 meters/second. Vector B = 10.0 i+2.00 j Newtons. What is the Dot product of these vectors?

Determine the dot or scalar product of the pairs of vectors shown in the figures. The magnitudes of the vectors are A = 7.00, B = 8.00, and D = 4.00, and the angles are as given. (a) A-B esc (b) A D ! 12 FI @ n Ā F2 60° А 60° # 2 20 F3 60° 30° $ 4 B 999 DOD F4 45 % F5 MacBook Air 6 F6 & 7 A F7 * 00 8 DII F8 ( 9 F9 0 F10 1 + = 8:12. delet

A force F= (20.0i +18.0j+ 24.0k) N acts on a small object of mass 95 kg. 1. What will be the magnitude of the acceleration of the object? 2. If the displacement vector dr =(10.0i + 8.0j) m, what is the work done by theforce? 3. The angle between F and dr?

Given two vectors: M = -3î + 6j – 5k and N = -2î + 3j +.k The vector dot product M· N equals A) 19 В) о с) 29 D 10 No Answer

A). Using the vectors on the grid above, what vector (cross) product results in the following calculation? B). Using the vectors on the grid above, what vector (cross) produet results in the following calculation? Show all work

A hockey puck of mass m is shot across a rough floor in a straight line. The puck moves in the positive x direction, and the coefficient of friction between the floor and the puck depends on position as u(x) = a + bx, where a is a dimensionless constant and b is a constant with units of m¹¹. Write an expression for the work done by kinetic friction as the puck moves from x= x₁ to x= x₂. Your answer should be in terms of m, x₁, x₂, a, b, and g (the acceleration due to gravity). W= В a g k P Submit Y b h m X1 Hint 8 d J 11 789 HOME 1^^ 4 5 6 1 2 3 0 NO BACKSPACE Feedback DEL I give up! END CLEAR

A 2.00-kg object has a velocity (6.20 1 - 1.80 ĵ) m/s. (Note: From the definition of the dot product, v² = v · V.) (a) What is its kinetic energy at this moment? 61.88 The kinetic energy depends on the speed, which is the magnitude of the velocity vector. J (b) Find the net work done on the object if its velocity changes to (8.00 î+ 4.00 ĵ) m/s. 50.12 How is the work done by the net force related to the change in kinetic energy? J

B (15.0 m) Ď (10.0 m) 30.0 53.0 25.0° Ċ (12.0 m) A (8.00 m) Consider the vectors shown above. What is the dot product ? O 55.0 m2 O -40.6 m2 O24.8 m2 O -55.0 m2 O 87.0 m2 O -24.8 m2

Using the definition of the scalar product, find the angle between the following two vectors: A = -2î + 4ĵ , B = 3î – 4ĵ + 2k.

If Force = (- 7, 9) and displacement = (-2,-2 ), find the work done from the two vector measurements .