In this experiment you studied the following net chemical reaction that we will call reaction (1): H,0, + 2 H* + 21 -1, + 2 H,0 (1) with the following proposed three-step reaction mechanism: H,0, + - OH" + HOI OH + H* - H,0 Step 1: (slow) Step 2: (very fast) Step 3: (fast) HOI + H* + -2 + H20 In neutral solution containing only hydrogen peroxide and iodide ion, a different net chemical reaction occurs: 2 H,0, - 2 H,0 + 0,(g) (2) The following three-step reaction mechanism has been proposed to explain reaction (2): H,0, +1 - OH + HOI Step 2a: (very fast) OH + HOI - 10 + H,0 Step 1: (slow) H20, + 10 I + H20 + 0,(g) 2 HA0 - 2 H0t O Show that when you sum the three reaction steps the net result is reaction (2): Step 3a: (fast)

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Chapter1: Chemical Foundations
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In this experiment you studied the following net chemical reaction that we will call reaction (1):
H,0, + 2 H* + 21 -1, + 2 H,0
(1)
with the following proposed three-step reaction mechanism:
Step 1: (slow)
H,O, +1 - OH" + HOI
Step 2: (very fast)
OH + H* - H,0
Step 3: (fast)
HOI + H* + 12 + H20
In neutral solution containing only hydrogen peroxide and iodide ion, a different net chemical reaction
occurs:
2 H,0, - 2 H,0 + 0,(g)
(2)
The following three-step reaction mechanism has been proposed to explain reaction (2):
Step 1: (slow)
H,O, +1 - OH + HOI
Step 2a: (very fast) OH + HOI - 10 + H,0
H,0, + 10 -I + H20 + 0,(g)
2 H0 2 H0 t OI
Show that when you sum the three reaction steps the net result is reaction (2):
Step 3a: (fast)
Transcribed Image Text:In this experiment you studied the following net chemical reaction that we will call reaction (1): H,0, + 2 H* + 21 -1, + 2 H,0 (1) with the following proposed three-step reaction mechanism: Step 1: (slow) H,O, +1 - OH" + HOI Step 2: (very fast) OH + H* - H,0 Step 3: (fast) HOI + H* + 12 + H20 In neutral solution containing only hydrogen peroxide and iodide ion, a different net chemical reaction occurs: 2 H,0, - 2 H,0 + 0,(g) (2) The following three-step reaction mechanism has been proposed to explain reaction (2): Step 1: (slow) H,O, +1 - OH + HOI Step 2a: (very fast) OH + HOI - 10 + H,0 H,0, + 10 -I + H20 + 0,(g) 2 H0 2 H0 t OI Show that when you sum the three reaction steps the net result is reaction (2): Step 3a: (fast)
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