In this case, system (1.8) is expressed as (af (Xn-1)+bf (*n-2)), Yn+1 = f (af (yn-1)+bf (yn-2)), (2.1) Xn+1 = for n e No. Since f is "1 – 1", from (2.1) f (Xn+1) = af (Xn-1)+bf (x,-2), f(Vn+1) = af (yn-1)+bf (yn-2), (2.2) for n E No. By using the change of variables f (xn) = un, and f (yn) = Vn, n>-2, (2.3) system (2.2) is transformed to the following one Un+1 = aun-1 + bun-2, Vn+1 = avn-1+ bvn-2, (2.4) for n e No. By taking a = 0, b= a, c= b in (1.4) and S, = Jn+1, for all n > -2, which is called generalized Padovan sequence, in (1.5), the solutions to equations in (2.4) are given by Un = uoJn+1+u-1Jn+2+ bu_2Jn, (2.5) Vn = VOJN+1+v-1Jn+2+bv_2Jn; (2.6) for n E No. From (2.3), (2.5) and (2.6), it follows that the general solution to system (2.2) is given by Xn = f(f (x0) Jn+1+f (x-1)Jn+2+bf (x-2) Jn), n> –2, Yn = f (f (vo) Jn+1+f (y-1)Jn+2+bf (y-2) Jn), n> -2. (2.7) (2.8) 2.2. Case 2: Pn = Xn, qn = Xn, I'n = Xn, Sn = Xn In this case, system (1.8) becomes Xn+1 =f(af (Xn-1)+bf (xn-2)), Yn+1 =f(af (xn-1)+bf (xn-2)), (2.9) for n E No. It should be first note that from the equations in (2.9) it immediately follows that x, = yn, for all n EN. From (2.7), the general solution to system (2.9) is Xn = Yn = f(f (xo) Jn+1+f (x=1) Jn+2+bf (x_2)Jn), n € N. (2.10)
In this case, system (1.8) is expressed as (af (Xn-1)+bf (*n-2)), Yn+1 = f (af (yn-1)+bf (yn-2)), (2.1) Xn+1 = for n e No. Since f is "1 – 1", from (2.1) f (Xn+1) = af (Xn-1)+bf (x,-2), f(Vn+1) = af (yn-1)+bf (yn-2), (2.2) for n E No. By using the change of variables f (xn) = un, and f (yn) = Vn, n>-2, (2.3) system (2.2) is transformed to the following one Un+1 = aun-1 + bun-2, Vn+1 = avn-1+ bvn-2, (2.4) for n e No. By taking a = 0, b= a, c= b in (1.4) and S, = Jn+1, for all n > -2, which is called generalized Padovan sequence, in (1.5), the solutions to equations in (2.4) are given by Un = uoJn+1+u-1Jn+2+ bu_2Jn, (2.5) Vn = VOJN+1+v-1Jn+2+bv_2Jn; (2.6) for n E No. From (2.3), (2.5) and (2.6), it follows that the general solution to system (2.2) is given by Xn = f(f (x0) Jn+1+f (x-1)Jn+2+bf (x-2) Jn), n> –2, Yn = f (f (vo) Jn+1+f (y-1)Jn+2+bf (y-2) Jn), n> -2. (2.7) (2.8) 2.2. Case 2: Pn = Xn, qn = Xn, I'n = Xn, Sn = Xn In this case, system (1.8) becomes Xn+1 =f(af (Xn-1)+bf (xn-2)), Yn+1 =f(af (xn-1)+bf (xn-2)), (2.9) for n E No. It should be first note that from the equations in (2.9) it immediately follows that x, = yn, for all n EN. From (2.7), the general solution to system (2.9) is Xn = Yn = f(f (xo) Jn+1+f (x=1) Jn+2+bf (x_2)Jn), n € N. (2.10)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Show me the steps of determine green and all information is here step by step
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,