Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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- What is the mass percent of Fe for each trial ? Mass of (NH4)2Ce(NO3)6 (in 100.00 mL) = 4.5038 g Mass of unknown (in 250.00 mL) = 10.000 g Trial # Volume of unknown solution (mL) Titration Volume (mL of Ce4+) Mass Percent(% Fe) 1 25.00 mL 7.20 mL 2 25.00 mL 7.40 mL 3 25.00 mL 7.60 mL 4 25.00 mL 7.50 mLarrow_forwardA 20.0 mL sample of commercial bleach was diluted with water to a 250.0 mL volumetric flask. A 50.0 mL aliquot of the diluted sample was treated with excess KI and starch. The liberated iodine was titrated with 0.399 M Na2S2O3, requiring 13.9 mL to reach the end point. (a) Identify the type of redox titration method used. (b) Identify the indicator and endpoint color. (c) Calculate the % w/v NaOCl in the sample.arrow_forwardA quantitative analysis for ethanol, C2H60, is accomplished by a redox back titration. Ethanol is oxidized to acetic acid, C2H402, using excess dichromate, 3+ Cr207 2-, which is reduced to Cr3*. The excess dichromate is titrated with Fe2*, giving C and Fe+ as products. In a typical analysis, a 5.00-mL sample of a brandy is diluted to 500 mL in a volumetric flask. A 10.00-mL sample is taken and the ethanol is removed by distillation and collected in 50.00 mL of an 2- acidified solution of 0.0200 M K2Cr207. Titration of the unreacted Cr207 requires 21.48 mL of 0.1014 M Fe2*. Calculate the %w/v ethanol in the brandy. Which is the titrant in this problem? C2H402 Fe2+ C2H60 O Cr207 2-arrow_forward
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- i need the answer quicklyarrow_forwardA 0.2653 g of pure potassium dichromate was dissolved in 15 mL of 1.5 M sulfuric acid and transferred to a 250.0 mL volumetric flask and diluted to the mark with distilled water. A 25.0 mL aliquot of this solution was transferred to another 250.0 mL volumetric flask and diluted to the mark with distilled water and this solution has an absorbance 0f 0.387 in a 2.00 cm cell. Calculate the molar absorptivity of potassium dichromate.arrow_forward= A 0.5099 g mixture of KCN (MW 65.116 g/mol) and NaCN (MW = 49.005 g/mol) was dissolved in water. AgNO, was added to the solution, precipitating all of the CN in solution as AgCN (MW : 133.886 g/mol). The dried precipitate weighed 1.184 g. Calculate the weight percent of KCN and NaCN in the original sample. KCN wt% = NaCN wt% = = % %arrow_forward
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